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Nataliya [291]
2 years ago
15

Calculate the decrease in gravitational potential energy of the ball as it moves down through the 0.90m the mass of the ball is

0.60kg
Physics
1 answer:
icang [17]2 years ago
8 0

Answer:

G.P.E = 5.292 Joules

Explanation:

Given the following data;

Mass = 0.6 kg

Height = 0.9 m

To find the gravitational potential energy;

Gravitational potential energy (GPE): it is an energy possessed by an object or body due to its position above the earth.

Mathematically, potential energy is given by the formula;

G.P.E = mgh

Where,

G.P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

But we know that acceleration due to gravity is equal to 9.8m/s²

G.P.E = 0.6*9.8*0.9

G.P.E = 5.292 Joules

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2 years ago
A basketball player jumps 76cm to get a rebound. How much time does he spend in the top 15cm of the jump (ascent and descent)?
vesna_86 [32]

Answer:

The time for final 15 cm of the jump equals 0.1423 seconds.

Explanation:

The initial velocity required by the basketball player to be able to jump 76 cm can be found using the third equation of kinematics as

v^2=u^2+2as

where

'v' is the final velocity of the player

'u' is the initial velocity of the player

'a' is acceleration due to gravity

's' is the height the player jumps

Since the final velocity at the maximum height should be 0 thus applying the values in the above equation we get

0^2=u^2-2\times 9.81\times 0.76\\\\\therefore u=\sqrt{2\times 9.81\times 0.76}=3.86m/s

Now the veocity of the palyer after he cover'sthe initial 61 cm of his journey can be similarly found as

v^{2}=3.86^2-2\times 9.81\times 0.66\\\\\therefore v=\sqrt{3.86^2-2\times 9.81\times 0.66}=1.3966m/s

Thus the time for the final 15 cm of the jump can be found by the first equation of kinematics as

v=u+at

where symbols have the usual meaning

Applying the given values we get

t=\frac{v-u}{g}\\\\t=\frac{0-1.3966}{-9.81}=0.1423seconds

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