a) mg = * ω
b)ω =
c)14.7 the magnitude of the initial acceleration of the end B when the string is cut.
<h3>What is Acceleration?</h3>
Acceleration is the rate of change of the velocity of an object with respect to time.
Given
A rod of length 56.0 cm and mass 1.40 kg is suspended by two strings which are 42.0 cm long, one at each end of the rod.
When the string is cut rod rotates about other end.
Let's take momentum equation about that end:
mg* = Iω [I = ]
a) mg = * ω
Angular acceleration:
b)ω =
c)Acceleration of end B:
a = lω= =
a = 14.7 [g=9.8]
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Answer:
18.43m
Explanation:
At the initial stage, the car accelerates at 2.0 m/s² for 6.7 seconds, to get the velocity of the car at this point, we will use the equation of motion;
v = u + at
v = 0+(2.0)(6.7)
v = 13.4m/s
The velocity of the car during this time is 13.4m/s.
Also, if the car slows down at a rate of 1.5m/s², we can also calculate the time it took for the car to decelerate (check the attachment for diagram).
v = u+at
v = 0
u = 13.4m/s
a = -1.5m/s² (deceleration is negative acceleration)
0 = 13.4+-1,5t
-13.4 = -1.5t
t = 13.4/1.5
t = 8.93s
Hence it took the car 8.93s to slow down for the next stop sign.
To calculate how far apart the stop signs are, we need to calculate the total distance AD according to the diagram
Distance covered = AD = 18.43m
HENCE THE STOP SIGNS ARE 18.43m apart
Answer:
And for this case we can write this expression like this:
The velocity would be given by the first derivate and we got:
And the maximum velocity would be:
Explanation:
For this case we have the following function for the position:
And for this case we can write this expression like this:
The velocity would be given by the first derivate and we got:
And the maximum velocity would be:
Answer:
Centripetal acceleration does not change speed but it changes direction as it is a single thing moving in a circular path. Most accelerations, like linear acceleration, cause things to move in a straight line. But, both centripetal and angular acceleration are vectors.