All categories

3 years ago

If an object is not moving, what do we know about the forces acting on it?

Physics

2 answers:

Nat2105 [25]3 years ago

7 0

I think it should be 'They are balanced' if I'm not wrong

erik [133]3 years ago

7 0

If the object is not moving then the forces acting on it are balanced. Also if the object is moving in a straight line at a constant speed than the forces on it are also balanced.

You might be interested in

A stack of books is sitting on a table. Which force is pulling downward on it?

Softa [21]

Gravity is the force pulling downward.

3 0

4 years ago

An object moving on a horizontal, frictionless surface makes a glancing collision with another object initially at rest on the s

ivann1987 [24]

Answer:

A) Momentum is always conserved, and kinetic energy may be conserved. TRUE

(B) Kinetic energy is always conserved, and momentum may be conserved. FALSE

(C) Momentum is always conserved, and kinetic energy is never conserved. FALSE

(D) Both momentum and kinetic energy are always conserved.

FALSE

(E) Neither momentum nor kinetic energy is conserved.

FALSE

Explanation:

A) Momentum is always conserved, and kinetic energy may be conserved.

Always the momentum is conserved for any collision.

(B) Kinetic energy is always conserved, and momentum may be conserved.

In inelastic collison the Kinetic energy is not conserved.

(C) Momentum is always conserved, and kinetic energy is never conserved.

For elastic collision the kinetic energy is always conserved.

(D) Both momentum and kinetic energy are always conserved.

The kinetic energy never is conserved in an inelastic collision.

(E) Neither momentum nor kinetic energy is conserved.

The momentum always is conserved.

7 0

4 years ago

You place an object 36.0 cm in front of a concave

vivado [14]

Given  :

Object position ( u ) = - 36 cm
focal length ( f ) = - 16 cm
image position ( v ) = ?

now, we know

=》

$\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$

=》

$\frac{1}{ - 16} = \frac{1}{ - 36} + \frac{1}{v}$

=》

$\frac{1}{v} = \frac{ - 1}{16} - \frac{ - 1}{36}$

=》

$\frac{1}{v} = \frac{ - 9 - ( - 4)}{144}$

=》

$\frac{1}{v} = \frac{ - 9 + 4}{144}$

=》

$\frac{1}{v} = \frac{ -5}{144}$

=》

$v = \frac{144}{ - 5}$

=》

 $v = - 28.8$ 

So, image position = 28.8 cm, at same side of object .

8 0

3 years ago

The speed of light in a vacuum is 2.998 x 108 m/s. what is its speed in km/h?

Artemon [7]

1079252848.8 kilometer per hour

7 0

3 years ago

Electronegativity___.

Paul [167]

Whats the question here ?

6 0

3 years ago