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Zinaida [17]
3 years ago
8

Please help, thanks(:

Mathematics
1 answer:
dexar [7]3 years ago
5 0
To solve this problem, we know that b = 1/2 and c = 1/4

The equation is 8(b/2) - (c + 4)

The problem is asking us to plug in 1/2 for b and 1/4 for c into the equation.

8(1/2/2) - (1/4 + 4) = 2 - 1/4 - 4 = -1/4 - 2 = - 9/4 (A)
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Your club has been asked to contribute to a service project benefiting a local charitable organization. You plan to buy a combin
FrozenT [24]

Answer:

the possible combinations of $5 and $10 gift cards your club can purchase are :

eight $5 gift cards and twelve $10 gift cards

nine $5 gift cards and eleven $10 gift cards

or ten each of $5 gift cards and $10 gift cards

Step-by-step explanation:

From the information given:

You plan to buy a combination of $5 and $10 gift cards

You plan to buy exactly 20 gift cards and want to spend between $150 and $160.

The objective is to determine the possible combinations of $5 and $10 gift cards your club can purchase?

Let assume the g is the number of the $5 gift cards bought;

then (20 - g) will be the number of the $10 gift card bought.

Thus; the compound inequality for the amount spent between $150 and $160 will be:

= 150 ≤ 5g + 10(20 - g) ≤ 160

=  150 ≤ 5g + 200 - 10g ≤ 160

= 150 ≤ 5g -10 g + 200 ≤ 160

= 150 ≤ -5g + 200 ≤ 160

= 150-200 ≤ -5g ≤ 160 -200

= -50  ≤ -5g ≤ -40

Divide through by -5

= 10 ≥ g ≥ 8

= 8 ≤ g ≤ 10

Thus; the possible combinations of $5 and $10 gift cards your club can purchase are :

eight $5 gift cards and twelve $10 gift cards  = i.e 8 ×$5 + 12 ×$10

= $40+$120

=$160

 

nine $5 gift cards and eleven $10 gift cards

 =  9 ×$5 + 11 ×$10

= $45 + $110

= $155

or ten each of $5 gift cards and $10 gift cards

=  10 ×$5 + 10 ×$10

= $50 + $100

= $150

These combinations falls in between the range of $150 and $160.

3 0
4 years ago
A LITTLE HELP PLEASE!! Find the area of this regular polygon. Round to the nearest tenth.
dem82 [27]

rounding to the nearest tenth will be 20

7 0
3 years ago
Rita bought some large packets of salt weighing 500grams each and some small packets of salt weighing 200 grams each. If she has
Rama09 [41]
L+S=8, L=8-S

500L+200S=2200, using L from above in this equation gives you:

500(8-S)+200S=2200

4000-500S+200S=2200

4000-300S=2200

-300S=-1800

S=6, and since L=8-S:

L=2

So Rita bought 2 large packets and 6 small packets.
5 0
3 years ago
5+3(q-4)=2(q+1) I don’t understand how to solve this question
Shtirlitz [24]

Answer:

q = 9

Step-by-step explanation:

5 + 3(q - 4) = 2(q + 1)

To solve, you need to get q by itself on one side.

5 + 3q - 12 = 2q + 2 --- distribute the multipliers next to the parenthesis

3q - 7 = 2q + 2 --- combine like terms

q - 7 = 2 --- subtract 2q from both sides

q = 9 --- add 7 to both sides


3 0
3 years ago
What equashion can be used to find two numbers those ratio are 3 to 2 and have the sum of 35
Tems11 [23]

We need to set up a system, rather than a single equation, because there are two variables involved.

The first equation represents the fact that the two numbers are in a 3:2 ratio:

\dfrac{x}{y}=\dfrac{3}{2} \iff x=\dfrac{3}{2}y

The second equation represents the fact that their sum is 35:

x+y=35

So, we have the following system:

\begin{cases}x = \dfrac{3}{2}y\\x+y=35\end{cases}

Using the expression for x in the first equation, the second one becomes

x+y=35 \iff \dfrac{3}{2}y+y=35 \iff\dfrac{5}{2}y=35 \iff 5y=70 \iff y = 14

which implies

x=35-y=35-14=21

7 0
3 years ago
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