Two lines are perpendicular if and only if the product of their slopes is - 1.
So, you just need to find the slope of each line and find out the product of their slopes.
I will do one example for you.
L1: y = 3x + 5
L2: y = - 3x + 14
L3: y = -x/3 + 14
The slope of a line is the coefficient of the x.
So the slopes are:
L1: slope 3
L2: slope -3
L3: slope -1/3
So now multiply the slopes of each pair of lines:
L1 and L2: 3 * (-3) = - 9 => No, they are not perpendicular
L2 and L3: (-3) * (-1/3) = 1 => No, they are not perpendicular
L1 and L3: (3) * (-1/3) = -1 => Yes, they are penpendicular.
Answer:
Option A
Step-by-step explanation:
<u>Given equation is</u>
=> 3y = 6x + 3
<u>In slope-intercept form, it becomes</u>
=> 3y = 3(2x+1)
=> y = 2x+1
So, Slope = m = 2
<u><em>Parallel lines have equal slope, So any line parallel to the above line would have its slope equal to 2</em></u>
=> Line parallel to 3y = 6x + 3 is y = 2x + 10
For this question you should say:
75/100 = 12/?
so the ? is your answer:
12*100/75 = 16 :)))
I hope this is helpful
have a nice day
<u>Top row - Left Row :</u>
Order : Left to Right
{11.7 - below(negative)} , {11.6 - below(negative)} , {12 - exactly filled} , {12.2 - above(positive)}
<u>Middle Row </u>:
Order : Left to Right
{11.1 - below(negative)} , {11.2 - below(negative)} , {11.9 - below(negative)} , {12.5 - above(positive)}
<u>Right Row </u>:
Order : Left to Right
{12 - exactly filled} , {11.4 - below(negative)} , {11.5 - below(negative)} , {10.8 - below(negative)}
