Answer:
0.30 mol/L
Explanation:
Mass = 108 g
Molar mass of glucose = 180.156 g/mol
The formula for the calculation of moles is shown below:
Thus,
Given Volume = 2 L
<u>Molarity = 0.3 mol/L</u>
Answer:
a.3-5 is the modal class.
1 mole of Ethanol molecule contains an Avogadro Number of molecules
1 mole of Ethanol molecule contains 6.02 * 10²³ molecules
3.5 moles of Ethanol will then contain: 3.5 * 6.02 * 10²³
= 2.107 * 10²⁴ molecules.
Answer:
29% is the final concentration
Explanation:
To solve this question we must find the volume of ethanol added and the volume of the whole solution. The concentration will be:
Volume ethanol / Total volume * 100
<em>Volume ethanol:</em>
10mL * 70% = 7mL ethanol
+
20mL * 80% = 16mL ethanol
= 23mL ethanol
<em>Total volume:</em>
10mL + 20mL + 50mL = 80mL
<em>Concentration:</em>
23mL / 80mL * 100
= 29% is the final concentration