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3 years ago

How many molecules are in 28 grams of nitrogen gas in balloons?

Chemistry

1 answer:

melomori [17]3 years ago

6 0

Answer:

$6.022\cdot 10^{23}$ molecules of nitrogen gas

Explanation:

In order to convert the mass of a given compound into the number of molecules, we need to:

identify the number of moles of a given compound dividing its mass by the molar mass, $n = \frac{m}{M}$ ,
multiply the number of moles by the Avogadro's constant which tells us that 1 mole contains $N_A = 6.022\cdot 10^{23}$ molecules.

In this problem:

$m_{N_2} = 28~g$

$M_{N_2} = 28.01~g/mol$

The number of particles is then found by:

$N_{N_2} = n_{N_2}\cdot N_A = \frac{m_{N_2}}{M_{N_2}} N_A = \frac{28 g}{28.01 g/mol}\cdot 6.022\cdot 10^{23} mol^{-1} = 6.022\cdot 10^{23}$

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Calculate the percentage by mass of the indicated element in the following compounds. Hydrogen in ascorbic acid, HC6H7O6, also k

Scorpion4ik [409]

Answer: The mass percent of hydrogen in ascorbic acid is 4.5 %

Explanation:

In $C_6H_8O_6$ , there are 6 carbon atoms, 8 hydrogen atoms and 6 oxygen atoms.

To calculate the mass percent of element in a given compound, we use the formula:

$\text{Mass percent of hydrogen}=\frac{\text{Mass of hydrogen}}{\text{Molar mass of ascorbic acid}}\times 100$

Mass of hydrogen = $8\times 1g/mol=8g$

Molar Mass of ascorbic acid = $6\times 12g/mol+8\times 1g/mol+6\times 16g/mol=176g$

Putting values in above equation, we get:

$\text{Mass percent of hydrogen}=\frac{8g}{176}\times 100=4.5\%$

Hence, the mass percent of of hydrogen in ascorbic acid is 4.5 %.

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3 years ago

suppose the heat of neutralization had ben determined using a glass beaker instead of a polystyrene coffee cup.how would the me

nalin [4]

Answer: Glass has a much higher specific heat than styrofoam so more of the energy produced will go into heating the glass. This quantity of heat will be lost (unaccounted for) hence the delta t in the calculation will be too small and the heat of neutralization will be lower.

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3 years ago

Who discovered the first real evidence of the big bang?

Sonbull [250]

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4 years ago

Read 2 more answers

36. Write a balanced chemical equation for each chemical reaction. (a) Solid copper reacts with solid sulfur to form solid coppe

stiks02 [169]

Answer:

a) 2Cu(s) + S(s) → Cu₂S(s)

b) 2SO₂(g) + O₂(g) → 2SO₃(g)

c) 4HCl(aq) + MnO₂(s) → MnCl₂(aq) + 2H₂O(l) + Cl₂(g)

d) C₆H₆(l) + 15/2 O₂(g) → 6CO₂(g) + 3H₂O(l)

Explanation:

First, we have to write the chemical formulas for reactants and products. Then, to identify which is the state of matter of each compound (liquid: l, solid: s, aqueous: aq, gas: g). Finally, we write the equation and balance the atoms.

a) Solid copper reacts with solid sulfur to form solid copper(I) sulfide.

Reactants: solid copper (Cu(s)) and solid sulfur (S(s)). Product: copper(I) sulfide (Cu₂S) because sulfur anion has two negative charges (S⁻²) and we need two copper ions with one positive charge (Cu⁺) to obtain the neutral compound.

The balanced requires a coefficient of 2 for Cu(s) to balance the 2 Cu atoms on the products side:

2Cu(s) + S(s) → Cu₂S(s)

(b) Sulfur dioxide gas reacts with oxygen gas to form sulfur trioxide gas.

Reactants: sulfur dioxide (SO₂) and oxygen gas (which is a diatomic molecule: O₂). Products: sulfur trioxide gas (SO₃(s)).

The balanced equation is:

2SO₂(g) + O₂(g) → 2SO₃(g)

We need a coefficient of 2 for SO₂ and SO₃ to balance O and S atoms.

(c) Aqueous hydrochloric acid reacts with solid manganese(IV) oxide to form aqueous manganese(II) chloride, liquid water, and chlorine gas.

Reactants: aqueous hydrochloric acid (HCl(aq)) and solid manganese (IV) oxide (MnO₂(s), because we need two oxygen anions O²⁻ to neutralize 4 positive charges in Mn IV). Products: aqueous manganese(II) chloride (MnCl₂, because we need two chloride ions Cl⁻ to neutralize two positive charges in Mn(II)), liquid water (H₂O), and chlorine gas (Cl₂, because it is a diatomic molecule).

The balanced chemical equation is:

4HCl(aq) + MnO₂(s) → MnCl₂(aq) + 2H₂O(l) + Cl₂(g)

(d) Liquid benzene (C₆H₆) reacts with gaseous oxygen to form carbon dioxide and liquid water.

Reactants: benzene (C₆H₆) and gaseous oxygen (O₂). Products: carbon dioxide (CO₂, because C has valence IV) and liquid water (H₂O).

The balanced chemical equation is:

C₆H₆(l) + 15/2 O₂(g) → 6CO₂(g) + 3H₂O(l)

In this case, we need a coefficient of 15/2 for O₂ because on the product side there are 15 atoms of O (12 in CO₂ and 3 in H₂O).

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3 years ago

What is the mole ratio of N2 to H2 to NH3?

Alexeev081 [22]

Answer:

the answer is 1:3:2

Hope this helps, let me know if you need any other help, Stoichiometry is hard

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4 years ago