Inert gas does not affect the equilibrium position:
It is because the partial pressures of the reaction components remain the same.
What is Inert Gas?
- Under a given set of conditions, an inert gas is a gas that does not undergo chemical reactions.
- The noble gases (helium, neon, argon, krypton, xenon, and radon) were previously known as "inert gases" due to their perceived lack of involvement in any biochemical processes.
- Because inert gases are non-reactive, they do not affect equilibrium partial pressures and thus do not affect volume.
- An inert gas does not react with the reactants or products; it does not change the concentration of the products and reactants. Furthermore, because the volume is constant, the concentrations are unaffected. As a result, this does not affect equilibrium.
The equilibrium position won't change if an inert gas is added. A volume change won't change the equilibrium position if the total moles of gas in the products and reactants are the same. When the volume is reduced, the process changes to create fewer moles of gas.
Learn more about the inert gas here,
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Answer: 13 grams
Explanation:
The quantity of heat energy (Q) released from a heated substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)
Thus, Q = MCΦ
Since,
Q = 202.8 Joules
Mass of silver = ?
C = 0.240 J/g °C.
Φ = 65°C
Then, Q = MCΦ
202.8J = M x 0.240 J/g °C x 65°C
202.8J = M x 15.6 J/g
M = (202.8J / 15.6 J/g)
M = 13 g
Thus, the mass of silver is 13 grams
Answer:
a) 24.7 mol
b) 790 g
Explanation:
Step 1: Given data
- Volume of the chamber (V): 200. L
- Room temperature (T): 23 °C
- Pressure of the gas (P): 3.00 atm
Step 2: Convert "T" to Kelvin
We will use the following expression.
K = °C + 273.15
K = 23°C + 273.15 = 296 K
Step 3: Calculate the moles (n) of oxygen
We will use the ideal gas equation.
P × V = n × R × T
n = P × V/R × T
n = 3.00 atm × 200. L/(0.0821 atm.L/mol.K) × 296 K = 24.7 mol
Step 4: Calculate the mass (m) corresponding to 24.7 moles of oxygen
The molar mass (M) of oxygen ga sis 32.00 g/mol. We will calculate the mass of oxygen using the following expression.
m = n × M
m = 24.7 mol × 32.00 g/mol = 790 g
Answer:
A. Ba(NO₃)₂(aq) + Na₂CO₃(aq)
Explanation:
- The reaction between aqueous Ba(NO₃)₂ and Na₂CO₃ is a precipitation reaction.
- The complete equation for the reaction is;
Ba(NO₃)₂(aq) + Na₂CO₃(aq) → BaCO₃(s) + NaNO₃(aq)
- Barium carbonate is the precipitate formed during the reaction.
- All nitrates are soluble in water and all salts of sodium are soluble in water, therefore, Ba(NO₃)₂, Na₂CO3, and NaNO₃ are soluble in water.
- Precipitation reaction involves reaction of soluble salts to form a precipitate as one of the product.
