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Ghella [55]
3 years ago
7

If 4.70 L of CO2 gas at 22 ∘C at 789 mmHg is used, what is the final volume, in liters, of the gas at 37 ∘C and a pressure of 75

5 mmHg , if the amount of CO2 remains the same
Chemistry
1 answer:
lutik1710 [3]3 years ago
5 0

Answer:

Final Volume = 5.18 Liters

Explanation:

Initial Condition:

P1 = 789 mm Hg x (1/760) atm /mm Hg = 1.038 atm

T1 = 22° C = 273 + 22 = 295 K

V1 = 4.7 L

Final Condition:

P2 = 755 mm Hg x (1/760) atm /mm Hg = 0.99 atm

T2 = 37° C = 273 + 37 = 310 K

V2 = ?

Since, (P1 x V1) / T1 =  (P2 x V2) / T2,

Therefore,

⇒ (1.038)(4.7) / 295 = (0.99)(V2) / 310

⇒ V2 = 5.18 L (Final Volume)

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Which of these figures probably shows a sugar solution containing a small amount of sugar dissolved in water
Vesnalui [34]

Answer:

The correct answer is Sugar has a greater solubility than sand.

Sugar will easily dissolve in water because it has a lower density than sand, therefore it has a greater solubility.

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4 years ago
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What is the empirical formula for a compound that is 31.9% potassium, 28.9% chlorine, and 39.2% oxygen?
notsponge [240]
The  empirical formula  for a compound   is KClO3

     Explanation 
 
find  the  moles of each  element
moles  = % composition/molar  mass

molar  mass of  of  potassium =39g/mol ,chlorine = 35.5 g/mol, oxygen =16 g/mol

moles  of potassium  =  31.9 / 39 = 0.818  moles
moles of  chlorine    = 28.9/35.5 = 0.814 moles
moles of   oxygen  =  39.2/  16 =  2.45  moles


find the  mole ratio  by  dividing   with  the smallest  mole = 0.814  moles

potassium = 0.818/0.814  =1  
chlorine  =  0.814/0.814 = 1
oxygen =  2.45 /0.814 =3 


the empirical  formula   is therefore = KClO3
7 0
4 years ago
Different measurements are expressed in different units. Choose the correct Sl units for the lo
swat32

Answer:

The SI units for measuring the velocity of the car: meters per second (m/s)

The Sl units for measuring the acceleration of the car: meters per second squared  (m/s^2)

The SI units for measuring force:  Newton (N)

The SI units for measuring mass: kilograms (kg)

Explanation:

Système international (SI) or International System of Units consist of a list of unit measurement that mostly used by scientist. The scientist from a different country might use different unit that makes them have to convert the result of each other. The usage of the same unit measurement will help the scientist to read that publication easier, make it easier to share and discuss any topic. The unit used is metric since the decimal system also makes the conversion of a unit easier.  

8 0
3 years ago
HELPPPPPPPPPP!!!!!!!!!!!!!!
SOVA2 [1]
The Answer is D cause of the people going back and forth.
4 0
4 years ago
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Question 2 of 50
wolverine [178]

The thermal decomposition of calcium carbonate will produce 14 g of calcium oxide. The stoichiometric ratio of calcium carbonate to calcium oxide is 1:1, therefore the number of moles of calcium carbonate decomposed is equal to the number of moles of calcium oxide formed.

Further Explanation:

To solve this problem, follow the steps below:

  1. Write the balanced chemical equation for the given reaction.
  2. Convert the mass of calcium carbonate into moles.
  3. Determine the number of moles of calcium oxide formed by using the stoichiometric ratio for calcium oxide and calcium carbonate based on the coefficient of the chemical equation.
  4. Convert the number of moles of calcium oxide into mass.

Solving the given problem using the steps above:

STEP 1: The balanced chemical equation for the given reaction is:

CaCO_{3} \rightarrow \ CaO \ + \ CO_{2}

STEP 2: Convert the mass of calcium carbonate into moles using the molar mass of calcium carbonate.

mol \ CaCO_{3} \ = 25 \ g \ CaCO_{3} \ (\frac{1 \ mol \ CaCO_{3}}{100.0869 \ g \ CaCO_{3}})\\ \\\boxed {mol \ CaCO_{3} \ = 0.2498 \ mol}

STEP 3: Use the stoichiometric ratio to determine the number of moles of CaO formed.

For every mole of calcium carbonate decomposed, one more of a calcium oxide is formed. Therefore,

mol \ CaO \ = 0.2498 \ mol

STEP 4: Convert the moles of CaO into mass of CaO using its molar mass.

mass \ CaO \ = 0.2498 \ mol \ CaO \ (\frac{56.0774 \ g \ CaO}{1 \ mol \ CaO})\\ \\mass \ CaO \ = 14.008 \ g

Since there are only 2 significant figures in the given, the final answer must have the same number of significant figures.

Therefore,

\boxed {mass \ CaO \ = 14 \ g}

Learn More

  1. Learn more about stoichiometry brainly.com/question/12979299
  2. Learn more about mole conversion brainly.com/question/12972204
  3. Learn more about limiting reactants brainly.com/question/12979491

Keywords: thermal decomposition, stoichiometry

5 0
3 years ago
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