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Fofino [41]
3 years ago
13

How is a pure substance different from a mixture?

Chemistry
2 answers:
Troyanec [42]3 years ago
8 0

Answer:

A pure substance is different from a mixture in that <u><em>mixtures are made up of more than on component</em></u>

Explanation:

A pure substance is a substance that is homogeneous and invariable (fixed), and it is not possible to separate or divide it into more substances. For example, water has the formula H2O and is always the same. This indicates that it is formed by molecules in which there are 2 hydrogen atoms and 1 oxygen atom. If I changed that formula, it would be another different substance.

A pure substance cannot be broken down into other simpler substances using physical methods.

A pure substance has its own or defined characteristic properties.

A pure substance can be both a chemical element and a compound, which are formed by atoms or molecules of the same nature.

On the other hand, a mixture is the union of two pure substances or compounds (which have their individual properties), and have a variable chemical composition. They can be separated by chemical or physical means and obtain the components that form the mixtures. They are formed by atoms and molecules of different nature.

The mixtures can be homogeneous (whose composition and properties are uniform in any part of a given sample, such as sugar dissolved in water) or heterogeneous (those in which at a glance it is easy to identify the different components that make them up; for example water and oil or water and sand)

Given the above, it is possible to say that <u><em>a pure substance differs from a mixture in that mixtures are made up of more than on component</em></u>

svlad2 [7]3 years ago
3 0

b.) mixtures are made up of more than on component. A pure substance is like a diatomic element, like O2, while a mixture is more like a salad, and can be separated by physical means.

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What is the difference between alkali metals and halogens?
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<h3>→soft and reactive metals. </h3>

Explanation:

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2 years ago
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How long, in seconds, would it take for the concentration of A to decrease from 0.860 M to 0.310 M?
kogti [31]

Answer:

2.038 seconds.

Explanation:

So, in the question above we are given the following parameters in order to solve this question. We are given a rate constant of 0.500 s^-, initial concentration= 0.860 M and final concentration= 0.310 M,the time,t =??.

Assuming that the equation for the first order of reaction is given below,that is;

A ---------------------------------> products.

Recall the formula below;

B= B° e^-kt.

Therefore, e^-kt = B/B°.

-kt = ln B/B°.

kt= ln B°/B.

Where B° and B are the amount of the initial concentration and the amount of the concentration remaining, k is the rate constant and t = time taken for the concentration to decrease.

So, we have; time taken,t = ln( 0.860/.310)/0.500.

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6 0
3 years ago
An aqueous solution is found to be 3.64% potassium nitrate by mass, how many grams of solution should I evaporate the water from
Sidana [21]

Answer:

513.74 g of solution

Explanation:

% Mass grams are defined as the <em>grams that are dissolved in salt</em> (in this case, it would be <em>potassium nitrate</em>) <em>dissolved every 100 g of the solution</em>. Having this information, you can calculate the amount of solution that has dissolved 18.7 g of potassium nitrate, which is what we want to obtain.

The relationship is:

3.64 g of potassium nitrate _____ 100 g solution

18.7 g of potassium nitrate _____ X = 513.74 g of solution

Calculation: 18.7g x 100g / 3.64g = 513.74 g of solution

So, <em>I need 513.74 g of solution to get 18.7g of potassium nitrate by evaporating it</em>.

8 0
3 years ago
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