Answer:
x = 5 and y =4
Explanation:
An alkane is a hydrocarbon of general molecular formula CnH2n+2. The general formula for balancing the combustion equation of any alkane is;
CnH2n+2 + 3n+1/2O2 ------> nCO2 + (n+1) H2O
Where n is the number of carbon atoms in the alkane.
In C3H8 , n=3 so;
C3H2(3)+2 + 3(3)+1/2O2 ------> 3CO2 + (3+1) H2O
Then;
C3H8 + 5O2 ------> 3CO2 + 4H2O
Therefore;
x = 5 and y =4
Explanation:
cl2 = 50/71
mole of cl2 = 0.704
no.of molecules = mole × avagadro no.
no of molecules = 0.704× 6.022×10²³
no. of molecules = 4.23×10²³
Moles= grams of compound/molar mass of compound ??
55.8 grams Would be the answer
first find the atomic weight of CH3 which would be
atomic weight: 12.011 (3×1.008) = 36.32 g/mol
then find the moles in the given mass
36.32 ÷ 45.7 = 0.794
I HOPE I'M NOT WRONG I HAVENT DONE CHEM IN SO LONG
