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suter [353]
3 years ago
15

Contrast situations where work is done with different amounts of force to situations where no work is done such as standing stil

l???
Physics
1 answer:
uranmaximum [27]3 years ago
5 0
Picking up a sheet of paper . . . work done with small force
Picking up a glass of water . . . work done with moderate force
Picking up a huge boulder . . . work done with a great tremendous force
=================================
Standing still . . .
Holding your tongue out as far as it will go . . .
Holding your arm over your head for 3 days . . .
Holding a huge boulder motionless over your head . . .
Pushing on a brick wall . . .
Pushing as hard as you can against a truck with the wheels locked . . .
. . . . . No work done at all, because the force doesn't move through a distance.

<u>Work done = (force) times (distance)</u>

If the force doesn't move, then the distance is zero, and the work done is zero.
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The radioactive element polonium decays according to the law given below where Q0 is the initial amount and the time t is measur
kogti [31]

Answer:

1280 mg

Explanation:

Radioactive  decay is a phenomenon that occurs when a certain isotope of an element, said to be radioactive, decays, turning into a lighter nucleus and emitting radiation + energy in the process.

The radioactive decay of this isotope of polonium is described by the equation

Q(t)=Q_0 2^{-\frac{t}{140}}

where

Q(t) is the amount of polonium left after time t

Q_0 is the amount of polonium t time t = 0

140 is the half-life of the polonium, in days (it is the time it takes for the initial element to halve its amount)

IN this problem, we know that:

After t = 560 days, the amount of polonium left is Q(t)=80 mg. Therefore, we can re-arrange the equation, substituting t = 560 d, and solve for Q_0 to find the initial amount of polonium:

Q_0 = Q(t) \cdot 2^{\frac{t}{140}}=(80)\cdot 2^{\frac{560}{140}}=1280 mg

5 0
4 years ago
How long does it take for the Earth to make a complete revolution around the sun?
timurjin [86]

365 days so a year basically

4 0
3 years ago
Read 2 more answers
Which pm the following are likely to form a covalent bond
Alecsey [184]

Answer:

magneisuim and gold

Explanation:

8 0
4 years ago
Read 2 more answers
If 45,000 Joules of work done in 90 seconds results in how much power?
Arisa [49]
Don’t forget about the formulas!

P=E/T
E=P•T
T=E/P

P= 45,000J / 90sec

500W is your answer
8 0
3 years ago
Calculate the force required to accelerate<br> a 600 g ball from rest to 14 m/s in 0.1 s.
Evgen [1.6K]

<u>Statement</u><u>:</u>

A force is required to accelerate a 600 g ball from rest to 14 m/s in 0.1 s.

<u>To </u><u>find </u><u>out</u><u>:</u>

The force required to accelerate the ball.

<u>Solution</u><u>:</u>

  • Mass of the ball (m) = 600 g = 0.6 Kg
  • Initial velocity (u) = 0 m/s [it was at rest]
  • Final velocity (v) = 14 m/s
  • Time (t) = 0.1 s

  • Let the acceleration be a.
  • We know the equation of motion,
  • v = u + at

  • Therefore, putting the values in the above formula, we get
  • 14 m/s = 0 m/s + a × 0.1 s
  • or, 14 m/s ÷ 0.1 s = a
  • or, a = 140 m/s²

  • Let the force be F.
  • We know, the formula : F = ma

  • Putting the values in the above formula, we get
  • F = 0.6 Kg × 140 m/s²
  • or, F = 84 N

<u>Answer</u><u>:</u>

The force required to accelerate the ball is 84 N and this force acts along the direction of motion.

Hope you could understand.

If you have any query, feel free to ask.

5 0
3 years ago
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