Answer:
E=hf
Were, h = Planck constant 6.67*10^11
E=3.8*10^24 * 6.67*10^11= 2.508*q0^36j
The potential energy is stored in the chemical bonds of the food. When those bonds break up during the metabolic processes, the energy is released. After that, that energy is stored in the Adenosine Triphosphate bonds aka ATP. The simplest way to think is to think of food as the tightly bound atoms. When the chemical bonds between those atoms break, the stored energy in that food is released.
( (77/4) + 76/2 )/2 = 28.625 km/h is what i got
Answer:
The velocity of the ball before it hits the ground is 381.2 m/s
Explanation:
Given;
time taken to reach the ground, t = 38.9 s
The height of fall is given by;
h = ¹/₂gt²
h = ¹/₂(9.8)(38.9)²
h = 7414.73 m
The velocity of the ball before it hits the ground is given as;
v² = u² + 2gh
where;
u is the initial velocity of the on the root = 0
v is the final velocity of the ball before it hits the ground
v² = 2gh
v = √2gh
v = √(2 x 9.8 x 7414.73 )
v = 381.2 m/s
Therefore, the velocity of the ball before it hits the ground is 381.2 m/s
Hi,
To convert 3 days to seconds write this.
1h = 3600s
24h = 3600 · 24 = 86400
3 days = 3 · 86400 = 259200sec
Hope this helps.
r3t40
