Question

A load of 5.0N stretches a spring by 10cm the relaxed length is 40cm assuming that the proportional length is not exceeded determine the force constant of the spring​

Answer 1

Answer:

50 N/m

Explanation:

When a spring is stretched by a force, the relationship between the force applied and the stretching of hte spring is

$F=kx$

where

F is the force applied

k is the spring constant

x is the stretching of the spring

In this problem, we have:

F = 5.0 N is the force applied to the spring

x = 10 cm = 0.10 m is the stretching caused by the force

Solving for k, we find:

$k=\frac{F}{k}=\frac{5.0}{0.10}=50 N/m$