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mariarad [96]
4 years ago
11

Scientists have established that some of the layers of Earth are solid, some are liquid, and some are semi-fluid. Explain how th

e scientists are able to determine the liquid and solid layers. Use at least two pieces of evidence to support your answer.
Chemistry
2 answers:
matrenka [14]4 years ago
8 0

Answer: Several studies has been made in order to understand the layers of the earth. Some of the evidences that proved the existence of solid and liquid layers are as follows-

  1. According to the concept of Isostacy, the earth's crust is a like a solid  wooden block, that floats over a vast liquid which is compared here with the mantle. Due to the variation in the crustal density, the crust sinks or gets uplifted.
  2. From the geophysical point of view, the study of the seismic waves made clear that the earth is comprised of three distinct layers such as the crust, mantle and the core. Crust refers to to top layer, mantle is the middle part and core is the interior part of the earth which is divided into two types, inner core (solid in nature) and outer core (liquid in nature).
tigry1 [53]4 years ago
7 0
They can determine the liquid layers and solid layers by seismic waves
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A certain metal M forms a soluble sulfate salt MSO, Suppose the left half cell of a galvanic cell apparatus is filled with a 3.0
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E = 0.062 V

Explanation:

(a) See the attached file for the answer

(b)

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Read 2 more answers
Calculate the volume in liters of a M potassium dichromate solution that contains of potassium dichromate . Round your answer to
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The question is incomplete, here is the complete question:

Calculate the volume in liters of a 0.13 M potassium dichromate solution that contains 200. g of potassium dichromate . Round your answer to 2 significant digits.

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<u>Explanation:</u>

To calculate the volume of solution, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}

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0.13M=\frac{200}{294.15\times \text{Volume of solution}}\\\\\text{Volume of solution}=\frac{200}{294.15\times 0.13}=5.23L

Hence, the volume of solution is 5.2 L

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3 years ago
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