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Anna71 [15]
3 years ago
6

This equation indicates that the reaction absorbs heat. What is this type of reaction called? H2O + heat → H2 + O2 A. an exother

mic reaction B. a combustion reaction C. an endothermic reaction D. a heat-releasing reaction
Chemistry
1 answer:
Anastaziya [24]3 years ago
7 0
The answer is C. an endothermic reaction. The endothermic reaction means this reaction will absorb energy and exothermic reaction means this reaction will release energy.
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What is mass in g of 15.5 moles of calcium?
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Answer:

621.2090000000001 grams

Explanation:

1 moles Calcium to grams = 40.078 grams

15.5*40.078 = 621.2090000000001 g

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What is produced when an acid and an alkali react?
marta [7]
The answer is D: Salt and Water
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Potassium fluoride (KF, a salt, has a molecular weight of 58.10 grams. How many grams would be needed to make 1.0 liter of 5.0 m
AlladinOne [14]
The concentration of the solution is 5.0 molar, which is 5.0 mole/L.  So in the 1.0 L of 5.0 molar KF salt solution, the moles of KF is 5.0molar*1.0L=5.0 mole. The molecular weight of KF is given in the question as 58.10 gram/mole, so the grams of KF is 58.10 gram/mole * 5.0 mole = 290.5 gram.
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What is the relationship between absorbance and transmittance of a sample in a spectrophotometer? Plz help!!
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Explanation:

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2 years ago
Reynolds number E. What is the mean velocity u. (ft/s) and the Reynolds number Re = pu., D/ for 35 gpm (gallons per minute) of w
Novay_Z [31]

Answer:

The mean velocity is 13 ft/s.

The Reynolds number is 88,583 and it is dimensionless.

Explanation:

We have water flowing in a pipe of 1.05 in diameter.

The density is ρ=62.3 lb/ft and the viscosity is 1.2 cP.

The mean velocity can be calculated as

u=\frac{Q}{A}=\frac{Q}{\pi*D^2/4}=\frac{35gpm }{3.14*(1.05in)^2/4}\\\\  u=\frac{35}{0.865}*\frac{gal}{min}\frac{1}{in^2}*\frac{231in^3}{1gal}*\frac{1}{60s} \\\\    u=156\,in/s=13\,ft/s

The Reynolds number now can be calculated for this flow as

Re=\frac{\rho*u*D}{\mu}

being ρ: density, u: mean velocity of the fluid, D: internal diameter of the pipe and μ the dynamic viscosity.

To simplify the calculation, we can first make all the variables have coherent units.

<em>Viscosity</em>

\mu=1.2cP=\frac{1.2}{100}\frac{g}{cm*s}*\frac{1lb}{453.6g}*\frac{30.48cm}{1ft}= 0.0008\frac{lb}{ft*s}

<em>Diameter</em>

D=1.05in*(\frac{1ft}{12in} )=0.0875ft

Then the Reynolds number is

Re=\frac{\rho*u*D}{\mu}\\\\Re=62.3\frac{lb}{ft^3}*13\frac{ft}{s} *0.0875ft*\frac{1}{0.0008}*\frac{ft*s}{lb}\\\\Re=88,583

8 0
3 years ago
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