All categories

3 years ago

In parallel circuits total resistance will be less than the resistance of the least resistence device. HOW ? please helppp

Physics

1 answer:

Lorico [155]3 years ago

3 0

Explanation:

Resistors can be connected in two ways;

1. Series connection

2. Parallel connection

When resistors are connected in series, the effective resistance is simply by adding up Rtotal = R1 + R2 + R3...

But when the are connected in parallel the effective resistance is simply 1/Rt = 1/R1 + 1/R2 + 1/R3

You can choose any value for your R1, R2 and R3 try it and see for yourself.

Good luck

You might be interested in

What is the momentum of a cat(4kg) and running at 1.5 miles

V125BC [204]

Answer:
6kg m/s

Explanation:

Momentum = p=mxv
Momentum = mass x velocity
4kg x 1.5m= 6 kg m/s

4 0

3 years ago

They did a flu shot from McKinnon at 45° to the horizontal with an initial speed of 25 m/s and that is positioned at a horizonta

Margarita [4]

Answer:

The time taken for the daredevil to travel the 50 m horizontally is 2.83 s.

Explanation:

Given;

angle of projection, θ = 45°

initial speed of the projectile, u = 25 m/s

horizontal distance traveled by the projectile, x = 50 m

The time taken for the daredevil to travel the 50 m horizontally is calculated as;

$t =\frac{X}{u_x}$

where;

$u_x$ is the horizontal component of the velocity = uCosθ

$t =\frac{X}{u Cos \ \theta} \\\\t =\frac{50}{25 \times Cos(45)} \\\\t= \frac{50}{17.678} \\\\t = 2.83 \ s$

Therefore, the time taken for the daredevil to travel the 50 m horizontally is 2.83 s.

6 0

3 years ago

I need the answers to these questions if u dont mind

Nonamiya [84]

there’s no photo. brainly hasent been working for me today so not sure

3 0

3 years ago

Physical therapists know as you soak tired muscles in a hot tub, the water will cool down as you heat up. If a 67.9 kg person at

Lubov Fominskaja [6]

Answer:

c = 5032.8J/kg°C

Explanation:

the transfer of heat is given by

$Q_1=-Q_2\\\\Q=cm(T_f-T_i)$

c is the specific heat, m the mass and T the temperatures at equilibrium an at the beginning.

By replacing we obtain

$c_1m_1(T_f-T_{1i})=-c_2m_2(T_f-T_{2i})\\\\c_2=-\frac{c_1m_1(T_f-T_{1i})}{m_2(T_f-T_{2i})}=-\frac{(67.9kg)(4186J/kg\°C)(38.7\°C-37.1\°C)}{(50.2kg)(38.7\°C-40.5\°C)}\\\\c_2=5032.8\frac{J}{kg\°C}$

hope this helps!!

4 0

3 years ago

A carbon rod with a radius of 1.9 mm is used to make a resistor. What length of the carbon rod should be used to make a 3.7 Ω re

vladimir2022 [97]

Answer:

Length = 2.32 m

Explanation:

Let the length required be 'L'.

Given:

Resistance of the resistor (R) = 3.7 Ω

Radius of the rod (r) = 1.9 mm = 0.0019 m [1 mm = 0.001 m]

Resistivity of the material of rod (ρ) = $1.8\times 10^{-5}\ \Omega\cdot m$

First, let us find the area of the circular rod.

Area is given as:

$A=\pi r^2=3.14\times (0.0019)^2=1.13\times 10^{-5}\ m^2$

Now, the resistance of the material is given by the formula:

$R=\rho( \frac{L}{A})$

Express this in terms of 'L'. This gives,

$\rho\times L=R\times A\\\\L=\frac{R\times A}{\rho}$

Now, plug in the given values and solve for length 'L'. This gives,

$L=\frac{3.7\ \Omega\times 1.13\times 10^{-5}\ m^2}{1.8\times 10^{-5}\ \Omega\cdot m}\\\\L=\frac{4.181}{1.8}=2.32\ m$

Therefore, the length of the material required to make a resistor of 3.7 Ω is 2.32 m.

5 0

3 years ago