A positive charge, q1, of 5 µC is 3 × 10–2 m west of a positive charge, q2, of 2 µC. What is the magnitude and direction of the
1 answer:
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The refractive index for glycerine is 
, while for air it is 
.
When the light travels from a medium with greater refractive index to a medium with lower refractive index, there is a critical angle over which there is no refraction, but all the light is reflected. This critical angle is given by:
where n1 and n2 are the refractive indices of the two mediums. If we susbtitute the refractive index of glycerine and air in the formula, we find the critical angle for this case:
When the light travels from a medium with greater refractive index to a medium with lower refractive index, there is a critical angle over which there is no refraction, but all the light is reflected. This critical angle is given by:
where n1 and n2 are the refractive indices of the two mediums. If we susbtitute the refractive index of glycerine and air in the formula, we find the critical angle for this case:
Answer:
2.83 m
Explanation:
The relationship between frequency and wavelength for an electromagnetic wave is given by
where
is the wavelength
is the speed of light
is the frequency
For the FM radio waves in this problem, we have:
is the minimum frequency, so the maximum wavelength is
The maximum frequency is instead
Therefore, the minimum wavelength is
So, the wavelength at the beginning of the range is 2.83 m.