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Ad libitum [116K]
3 years ago
7

A positive charge, q1, of 5 µC is 3 × 10–2 m west of a positive charge, q2, of 2 µC. What is the magnitude and direction of the

electrical force, Fe, applied by q1 on q2?
Physics
1 answer:
EastWind [94]3 years ago
4 0
The law you need is :
lets call the constant c = 4pi*epsilon naught*r2.
where r is radius ( or seperation of the charges). epsilon naught is a constant of about 8.85*10^-12 or something like that. and 4 pi is just 4 times pi.
the actual equation is 
FORCE= (q1*q2)/c

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3 years ago
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