All categories

3 years ago

Which of the following is the perimeter of a triangle with side lengths of 18 cm, 26 cm, and 32 cm?

Mathematics

1 answer:

pashok25 [27]3 years ago

7 0

Answer:

76 cm

Step-by-step explanation:

To find the perimeter, add up all of the side lengths.

18 cm + 26 cm + 32 cm = 76 cm

I hope this helps :))

You might be interested in

The distance d of a particle moving in a straight line is given by d(t) = 2t^3 + 5t – 2, where t is given in seconds and d is me

Amanda [17]

Answer: 299 m/s

Step-by-step explanation:

The first step is to take the first derivative of the equation given. This will give us the equation for velocity which we will then substitute the 7 in for t.

To derive the equation you multiply the coefficient by the power of the variable, then subtract one from the variable.

v(t) = 6t^2 + 5

Now input 7 in for t to find the velocity.

v(7) = 6(7)^2 + 5

v(7) = 299 m/s

6 0

3 years ago

A rectangle has a width of 3 units. The rectangle's length is 5 times its width.

Korolek [52]

Answer:

width=3

then length=5×3

now,

Area=l×b

= 15×3

=45

8 0

2 years ago

Read 2 more answers

Please help me give me right answer pleaseeeeeeeeeeee

Harlamova29_29 [7]

Answer:

7 x 2, 14, the area, then use pie, 3.14 to get the circle

Step-by-step explanation:

3 0

1 year ago

Click on the picture to look at some equivalent fractions. Look at them closely. Can you see a relationship of any kind between

Vera_Pavlovna [14]

when you simplify 2/4 it equals 1/2. Making them both equal the same.

2/3 when you double the numbers to make a bigger fraction you make 4/6.

2x2 = 4/ 3x3= /6 = 4/6

3/9 simplified is 1/3. Three goes into three one time, making the top one and three goes into 9 three times making the bottom 3.

When 9/12 is rounded down it is equivalent to 3/4

5 0

2 years ago

Read 2 more answers

A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a

Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 = 0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = $2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750$

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

$W_2 = \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5$

The work done in pulling half the rope, W₂ = 562.5 lb·ft

6 0

2 years ago