Answer:
For this case we have the following info related to the time to prepare a return

And we select a sample size =49>30 and we are interested in determine the standard deviation for the sample mean. From the central limit theorem we know that the distribution for the sample mean
is given by:
And the standard deviation would be:

And the best answer would be
b. 2 minutes
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".
Solution to the problem
For this case we have the following info related to the time to prepare a return

And we select a sample size =49>30 and we are interested in determine the standard deviation for the sample mean. From the central limit theorem we know that the distribution for the sample mean
is given by:
And the standard deviation would be:

And the best answer would be
b. 2 minutes
Answer:
2/9
Step-by-step explanation:
Simplify 80°/360°
Jac fxddmcrrnfhthfjgjjfjffjfhfjthht tntnfntj4r
The expression is equivalent to 1.5 raised to the fifth power divided by 0.7 raised to the fourth power, all raised to the third power is; Option A; 1.5 raised to the fifteenth power divided by 0.7 raised to the twelfth power
<h3>How to solve exponents?</h3>
We want to find the expression that is equivalent to 1.5 raised to the fifth power divided by 0.7 raised to the fourth power, all raised to the third power.
The sentence above can be expressed as;
((1.5⁵)/(0.7⁴))³
This can be broken down into;
[1.5^(5 * 3)]/(0.7^(4 * 3))
1.5¹⁵/0.7¹²
Looking at the options, the only correct one is;
Option A; 1.5 raised to the fifteenth power divided by 0.7 raised to the twelfth power
Read more about Exponents at; brainly.com/question/11975096
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Answer:
1
Step-by-step explanation:
Equation of variance:
Total Variance = sum (i=1, N) {c^2,variance^2}
= c1^2*variance1^2 + c2^2*variance2^2 + .....
Variance of X = 1
Variance of Y = 5
Variance of Y - 2X = (1^2)*(5) - (2^2)**(1)
= 5 - 4 = 1