<span>a.
</span>Do you
have sufficient funds to estimate the population mean for the attribute of
interest with a 95% confidence interval 4 units width? Assume that sd= 12
n= {[(Zalpha/2)^2]*[sd]^2}/
se^2
n=
(1.96)^2*(12)^2/ (2)^2
n=
138.297 rounded up to 139
<span>There
is not enough funds for this one
since you’ll need 139 pieces and it costs 10 a piece, you’ll need 1390.</span>
b.
90% confidence interval
n= {[(Zalpha/2)^2]*[sd]^2}/
se^2
n=
(1.645)^2*(12)^2/ (2)^2
n=98
There is enough
funds since 98 pieces for 10 a piece is equal to 980.
Answer:
Step-by-step explanation:
The given system is:
4x-3y=8
5x-2y=-11
We make x the subject in the top equation to get:
Plug this expression for x in the bottom equation to get
We expand to obtain
Multiply through by 4
Group similar terms
This means
A. The y-intercept is y = −0.05 x + 16 and the x-intercept is x = −20y + 320
B. The x-intercept represents the number of miles the car has traveled.
C. The y-intercept represents the number of gas in gallons.
The coordinates of the endpoints of line segments T'V' are; T'(-1, 2) and V'(0, 1).
<h3>What are the coordinates of the endpoints of the segment T'V'?</h3>
It follows from the task content that the transformation involved in the formation of the image from the pre-image is dilation by a scale factor of 1/4.
On this note, given that the coordinates of T and V from the task content are; (-4, 8) and (0,4), it follows that the coordinates of the endpoints as required are; T'(-1, 2) and V'(0, 1).
Read more on dilations;
brainly.com/question/3457976
#SPJ1
In total he is laying $3,545
