We have been given the OH⁻ ion concentration, we can calculate the pOH concentration.
pOH = -log [OH⁻]
pOH = - log (5.5 x 10⁻⁵ M)
pOH = 4.26
we can then calculate the pH value
pH + pOH = 14
pH = 14 - 4.26
pH = 9.74
since pH > 7 the solution is basic.
by knowing the pH value, we can calculate the H₃O⁺ concentration
pH = - log[H₃O⁺]
[H₃O⁺] = antilog (-pH) = antilog (-9.74)
[H₃O⁺] = 1.82 x 10⁻¹⁰ M
Answer:
2.15 mg of uranium-238 decays
Explanation:
For decay of radioactive nuclide-
where N is amount of radioactive nuclide after t time, 
is initial amount of radioactive nuclide and 
is half life of radioactive nuclide
Here 
, 
and 
So,
so, N = 2.446 mg
mass of uranium-238 decays = (4.60-2.446) mg = 2.15 mg
The correct answer is passive transport.
When molecules are moved from areas of high concentration to areas of low concentration in order to gain energy, that is considered to be passive transport. If the opposite happens, then that would be active transport.
