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Anarel [89]
3 years ago
8

Amino acids are the building blocks of proteins. The simplest amino acid is glycine . Draw a Lewis structure for glycine. (Hint:

The central atoms in the skeletal structure are nitrogen bonded to carbon which is bonded to another carbon. The two oxygen atoms are bonded directly to the right-most carbon atom.

Chemistry
1 answer:
madam [21]3 years ago
5 0

Answer:

Sorry for the lack of precision, if you have any questions you can consult me again.

Explanation:

Glycine is an amino acid, forms proteins and is also called in its molecular chemical formula as C2H5NO2

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There are three sets of sketches below, showing the same pure molecular compound (hydrogen chloride, molecular formula ) at thre
RideAnS [48]

Answer:

The correct answer is - option C.

Explanation:

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Solid -114.8  - Ordered arrangement

Liquid -85.1c  - Less orderly arranged

Gaseous - Least orderly arranged

Thus, at —90 °C, HCl will be present 'in the liquid state,  At — 1 °C, HCl will be present in the gaseous state and at -129 °C, HCl will be present in the solid-state. So, the molecules will be organized in a more orderly manner .

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8 0
3 years ago
The addition of hydrochloric acid to a silver nitrate solution precipitates silver chloride according to the reaction:
Nimfa-mama [501]

Answer:

Enthalpy change for the reaction is -67716 J/mol.

Explanation:

Number of moles of AgNO_{3} in 50.0 mL of 0.100 M of AgNO_{3}

= Number of moles of HCl in 50.0 mL of 0.100 M of HCl

= \frac{0.100}{1000}\times 50.0 moles

= 0.00500 moles

According to balanced equation, 1 mol of AgNO_{3} reacts with 1 mol of HCl to form 1 mol of AgCl.

So, 0.00500 moles of AgNO_{3} react with 0.00500 moles of HCl to form 0.00500 moles of AgCl

Total volume of solution = (50.0+50.0) mL = 100.0 mL

So, mass of solution = (100.0\times 1.00) g = 100 g

Enthalpy change for the reaction = -(heat released during reaction)/(number of moles of AgCl formed)

= \frac{-m_{solution}\times C_{solution}\times \Delta T_{solution}}{0.00500mol}

= \frac{-100g\times 4.18\frac{J}{g.^{0}\textrm{C}}\times [24.21-23.40]^{0}\textrm{C}}{0.00500mol}

= -67716 J/mol

[m = mass, c = specific heat capacity, \Delta T = change in temperature and negative sign is included as it is an exothermic reaction]

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