answer:
39.9
Step-by-step explanation:
54= area of rectangle
28.26= area of the circle
divide circle area by 2
= 14.13
subtract half of circle from rectangle area
54- 14.13
= 39.9
Answer:
Skewed to the left
Step-by-step explanation:
Given


Required
The type of distribution
From the given data, we have:
--- Mean and Median are not equal
and
--- Median is greater than mean
<em>When the median is greater than the mean; the histogram is expected to be left skewed</em>
Answer:
I think the answer is A
Sorry if i am wrong
Step-by-step explanation:
Answer: ![\bold{\sqrt[4]{2} }](https://tex.z-dn.net/?f=%5Cbold%7B%5Csqrt%5B4%5D%7B2%7D%20%7D)
<u>Step-by-step explanation:</u>
![\dfrac{1}{2}\sqrt[4]{32} =\dfrac{1}{2}\sqrt[4]{2\cdot 2\cdot 2\cdot 2\cdot 2}=\dfrac{1}{2}\cdot 2\sqrt[4]{2}=\boxed{\sqrt[4]{2} }](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B2%7D%5Csqrt%5B4%5D%7B32%7D%20%3D%5Cdfrac%7B1%7D%7B2%7D%5Csqrt%5B4%5D%7B2%5Ccdot%202%5Ccdot%202%5Ccdot%202%5Ccdot%202%7D%3D%5Cdfrac%7B1%7D%7B2%7D%5Ccdot%202%5Csqrt%5B4%5D%7B2%7D%3D%5Cboxed%7B%5Csqrt%5B4%5D%7B2%7D%20%7D)
A) 
B)In 200 times he can hit 59 times !
<u>Step-by-step explanation:</u>
Here we have , A baseball player got a hit 19 times in his last 64 times at bat. We need to find the following :
a. What is the experimental probability that the player gets a hit in an at bat?
According to question ,
Favorable outcomes = 19
Total outcomes = 64
Probability = (Favorable outcomes)/(Total outcomes) i.e.
⇒ 
⇒ 
b. If the player comes up to bat 200 times in a season, about how many hits is he likely to get?
According to question , In 64 times he hit 19 times . In 1 time there's probability to hit 0.297 times! So ,In 200 times he can hit :
⇒ 
⇒ Hit = 59.36
Therefore , In 200 times he can hit 59 times !