Through what type of single pericyclic reaction did the reaction shown below proceed

Draw the three alkenes, each of formula C5H10, that will form 2-methylbutane upon hydrogenation?

tiny-mole [99]

Answer is in Word document below.
Hydrogenation is reaction of organic compound with hydrogen. In this chemical reaction, three alkenes react with hydrogen and produce alkanes. Double bond in alkenes breaks up and single bond is formed. Three alkenes are all 2-butene with one methyl group substituent.

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6 0

3 years ago

Without looking at the periodic table, identify the group, period, and

kobusy [5.1K]

the group : 2

periode : 6

block = 2

atomic number = 56

<h3>Further explanation </h3>

We can divide the periodic system into several parts:

1. Block s: groups 1 and 2 (having a configuration of 1s-7s) consist of active metals except for H (non-metals) and He (noble gases)

2. Block p: group 13-18 (has a 2p-6p configuration), also called a representative element because it includes metals, non-metals and metalloids

3. Block d: group 3-12 (having the 3d-6d configuration), are transition metal elements

4. Block f: Lanthanides and Actinides (having a 4f-5f configuration), are inner transition elements that are also metal

The element with the electron configuration : [Xe]6s²

The outer shell 6s² :

Electron configuration :

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s² : electron =56

group⇒valence electron ⇒2

period⇒the greatest value of the quantum number n⇒6

The element that is in period 6, and belongs to group 2 and has the atomic number 56 and in the block s

4 0

3 years ago

What is the most likely way a chemist would be involved in the production of<br> a computer chip?

ZanzabumX [31]

Answer: Computer chips are very complex, maybe there are things insode that chemists are familiar with. Maybe they can give insight about this.

Explanation:

4 0

3 years ago

How many unpaired electrons does boron have

never [62]

In the ground state, only one. But for bonding, all three valence electrons are used, and the atom acquires a slightly excited state.

4 0

3 years ago

For a molecule of hydrazoic acid (HN3, also known as hydrogen azide), the atoms are arranged as HNNN. One resonance form of HN3

disa [49]

Answer:

0; +1; -1

Explanation:

The resonance structure of HN₃ is shown below (you can also use horizontal dashes to represent the bonding pairs).

The molecule has 16 valence electrons, and each N atom has an octet.

To get the formal charges, cut the covalent bonds in half.

Each atom gets the electrons on its side of the cut.

Formal charge = valence electrons in isolated atom - electrons on bonded atom

FC = VE - BE

(a) On Nₐ

VE = 5

BE = 1 lone pair (2)+ 3 bonding electrons = 2 + 3 = 5

FC = 5 - 5 = 0.

(b) On Nb:

VE = 5

BE = 4 bonding electrons = 4

FC = 5 - 4 = +1

(c) On Nc:

VE = 6

BE = 2 lone pairs(4) + 2 bonding electrons = 4 + 2 = 6

FC = 5 - 6 = -1

7 0

3 years ago