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murzikaleks [220]
3 years ago
11

How many unpaired electrons does boron have

Chemistry
1 answer:
never [62]3 years ago
4 0

In the ground state, only one. But for bonding, all three valence electrons are used, and the atom acquires a slightly excited state.

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What is the mass of 8.90 moles of magnesium chloride, MgCl2?
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<span>(8.90/95.211) =0.09347 moles</span>
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What is the smallest identifiable unit of a compound
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Answer:A(n) molecule that is made up of atoms that are chemically bonded is the smallest recognizable unit of a compound.

Explanation:

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Convert 234 kJ to kcal. Only include the numerical value in your answer. Respond with the correct number of significant figures
Fiesta28 [93]

Answer:

234 KJ ≡ 55.887 Kcal

Explanation:

∴ J ≡ Kg/m².s² ≡ N.m = 0.2389 cal

∴ cal = 4.187 J

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4. Define power and explain how to determine power.
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5 0
3 years ago
Calculate the pH and fraction of dissociation ( α ) for each of the acetic acid ( CH 3 COOH , p K a = 4.756 ) solutions. A 0.002
marysya [2.9K]

Answer:

The degree of dissociation of acetic acid is 0.08448.

The pH of the solution is 3.72.

Explanation:

The pK_a=4.756

The value of the dissociation constant = K_a

pK_a=-\log[K_a]

K_a=10^{-4.756}=1.754\times 10^{-5}

Initial concentration of the acetic acid = [HAc] =c = 0.00225

Degree of dissociation = α

HAc\rightleftharpoons H^++Ac^-

Initially

c

At equilibrium ;

(c-cα)                                cα        cα

The expression of dissociation constant is given as:

K_a=\frac{[H^+][Ac^-]}{[HAc]}

1.754\times 10^{-5}=\frac{c\times \alpha \times c\times \alpha}{(c-c\alpha)}

1.754\times 10^{-5}=\frac{c\alpha ^2}{(1-\alpha)}

1.754\times 10^{-5}=\frac{0.00225 \alpha ^2}{(1-\alpha)}

Solving for α:

α = 0.08448

The degree of dissociation of acetic acid is 0.08448.

[H^+]=c\alpha = 0.00225M\times 0.08448=0.0001901 M

The pH of the solution ;

pH=-\log[H^+]

=-\log[0.0001901 M]=3.72

3 0
4 years ago
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