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In-s [12.5K]
3 years ago
7

Can you please solve this equation?

Mathematics
1 answer:
zmey [24]3 years ago
3 0

x = -52 4/17
 the full answer in attachments

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Which of the following graphs of exponential functions corresponds to a geometric sequence with a first term of 4 and a ratio of
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Answer: graph E.


A geometric sequence can be written as:

a_{n} = a_{1} \cdot r^{(n - 1)}

where:

a₁ = first term = 4

r = ratio = 0.5


Substituting the numbers, we have:

a_{n} = 4 \cdot (\frac{1}{2})^{n-1}

or else

f(x) = 4 \cdot (\frac{1}{2})^{x - 1}


This is an exponential function with base less than 1. Therefore, we can exclude graph C (which depicts a linear function), and graphs A and D (which depict an exponential function with base greater than 1).


In order to choose between graph B and E, let's evaluate the function in two different points:

f(1) = 4 \cdot (\frac{1}{2})^{1 - 1} = 4

f(2) = 4 \cdot (\frac{1}{2})^{2 - 1} = 4 \cdot \frac{1}{2} = 2


Therefore, we need to look for the graph passing through the points (1, 4) and (2, 2). That is graph E.




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Each member of a nine-person committee attends any given meeting of the committee with probability 1/2. What is the probability
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A suitable statistics calculator gives the probability that 6 or more show up as being about ...
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3 years ago
Without using a calculator, match each expression to the correct point.<br><br> Point<br> Expression
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Where is the photo?

Step-by-step explanation:

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You are flipping two standard coins.One coin is red and the other is blue.What is the probability of getting heads on the red co
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I Believe the answer is B
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choose the point-slope form and f the equation below that represents the line through the point (6,-3) and has a slope of 1/2
AveGali [126]

Answer:

The point-slope form of this equation would be y + 3 = 1/2(x - 6)

Step-by-step explanation:

In order to find this, start with the base form of point-slope form.

y - y1 = m(x - x1)

Now input the slope for m and the point for (x1, y1)

y - -3 = 1/2(x - 6)

y + 3 = 1/2(x - 6)


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3 years ago
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