<h3>
Answer: 35 (choice C)</h3>
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Explanation:
For any triangle, the three interior angles always add to 180.
D+E+F = 180
(7b+1) + (2b+1) + (b+8) = 180
(7b+2b+b) + (1+1+8) = 180
10b+10 = 180
10b = 180-10
10b = 170
b = 170/10
b = 17
Use this value of b to find the three angle measures
- D = 7b+1 = 7*17+1 = 119+1 = 120
- E = 2b+1 = 2*17+1 = 34+1 = 35 degrees
- F = b+8 = 17+8 = 25
As a check,
D+E+F = 120+35+25 = 120+60 = 180
which helps confirm the correct answers.
Median: The middle number when all the numbers are listed in order.
First, we would put our numbers in order from least to greatest.
0 - 0 - 1 - 1 - 1 - 2 - 2 - 2 - 4 - 4
Next, we need to find the middle number. When we cross of one number from the left and one number from the right and keep doing this, we come across two numbers that are in the middle. The two numbers that are in the middle are 1 and 2. We find the median by adding 2 and 1 together to get a sum of 3 and then divide it by 2 to get an answer of 1.5
The median of this set of numbers is 1.5
ANSWER
x coordinates of the intersection points
EXPLANATION
The given system of equations is:
We want to use the graph of these functions to solve
The point of the intersection of the graph gives the solution to the simultaneous equation above.
Hence the x-coordinates of the intersection points gives the solution set of
The last choice is correct.
Answer:
1) decay
2) growth
3) growth
Step-by-step explanation:
A generic exponential function can be written as:
f(x) = A*(r)^x
Where:
A is the initial amount of something.
r is the rate of growth.
x is the variable, usually, represents time.
if r > 1, we have an exponential growth.
if r < 1, we have an exponential decay.
1) f(x) = (3/4)^x
in this case we have:
A = 1
r = (3/4) = 0.75
Clearly, r < 1.
Then this is an exponential decay.
2) f(x) = (1/6)*4^x
In this case we have:
A = (1/6)
r = 4
Here we have r > 1.
Then this is an exponential growth.
3) f(x) = (1/4)*(5/2)^x
in this case we have:
A = 1/4
r = 5/2 = 2.5
here we have r > 1, then this is an exponential growth.
