$\frac{x^2+5x+6}{x-6} \div \frac{x^2-9}{2x-12} \\\\Now,\\Before\ touching\ the\ expression,\ lets\ look\ at\ the\ indiviual\ terms\ and\ try\ to factorize\ them.\\x^2+5x+6\\=(x^2+3x+2x+6)\\=x(x+3)+2(x+3)\\=(x+2)(x+3)\\\\x-6=(x-6)\\\\x^2-9\\=(x)^2-(3)^2\\=(x-3)(x+3)\\\\2x-12\\=2(x-6)\\\\Hence,\\\frac{x^2+5x+6}{x-6} \div \frac{x^2-9}{2x-12}\\=\frac{(x+3)(x+2)}{x-6} \div \frac{(x-3)(x+3)}{2(x-6)}\\By\ flipping\ the\ second\ term\ to\ its\ reciprocal, we\ get:\\$ $\frac{(x+3)(x+2)}{x-6} * \frac{2(x-6)}{(x-3)(x+3)}\\\\=(x+2)*\frac{2}{(x-3)} \\=\frac{2(x+2)}{(x-3)}$

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3 years ago

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How many miles can a bumblebee travel in one minute if it travels 6.4 miles per hour

goldfiish [28.3K]

Sorry I don't know I'm not that good at these kinds of things so so so sorry

3 0

3 years ago