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MAXImum [283]
3 years ago
5

Balance the below half-reaction, which takes place in acidic solution. cr2o72−(aq) → cr3 (aq) how many electrons are transferred

in the balanced half-reaction
Chemistry
1 answer:
daser333 [38]3 years ago
8 0
The equation is as follow,

                                          Cr₂O₇²⁻    →    Cr³⁺

Balance the Cr atoms,
                                          Cr₂O₇²⁻    →    2 Cr³⁺

Identify Oxidation Number of Elements on Both sides,

Left Hand Side;
                          Cr  =  +6
                           O  =  -2
Right Hand Side;
                          Cr  =  +3
                           O  =  -2

Means each Cr is gaining 3 electrons to change into +3 state, Hence, 6 electrons are gained by two Cr atoms, So,

                                       Cr₂O₇²⁻  +  6e⁻    →    2 Cr³⁺

Balance Oxygen atoms, as it is acidic medium, add H⁺ ion on the side containing large number of Oxygen atoms and H₂O on side containing less number of Oxygen atoms, So,

                                 H⁺  +  Cr₂O₇²⁻  +  6e⁻    →    2 Cr³⁺  +  H₂O

Now Balance H and O,

                          14 H⁺  +  Cr₂O₇²⁻  +  6e⁻    →    2 Cr³⁺  +  7 H₂O

6 electrons are transferred in this reaction.
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Answer:

1.00 × 10¹⁸

Explanation:

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The formula for the energy of a photon is

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<em>h</em> = 6.626 × 10⁻³⁴ J·s; <em>c</em> = 2.998 × 10⁸ m·s⁻¹

λ = 477 nm = 477 × 10⁻⁹ m                              Insert the values

<em>E</em> = (6.626 × 10⁻³⁴ × 2.998× 10⁸)/(477 × 10⁻⁹)

<em>E</em> = 4.165× 10⁻¹⁹ J

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