Answer: Discover ZEISS Solutions
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Answer:
389 mL solution
Explanation:
Step 1: Given data
- Concentration of the NaCl solution: 0.900% (m/v)
- Mass of sodium chloride: 3.50 g
- Volume of saline solution: ?
Step 2: Calculate the volume of saline solution
The concentration of the NaCl solution is 0.900% (m/v), that is, there are 0.900 g of NaCl every 100 mL of solution.
3.50 g NaCl × 100 mL solution/0.900 g NaCl = 389 mL solution
Answer:
The total pressure in the container is 2 atm (Option B)
Explanation:
Step 1: Data given
The initial pressure of the PCl5(g) is 1.00 atm
Volume of the container = 1.00 L
Step 2: The balanced equation
PCl5(g) ⇋ PCl3(g) + Cl2(g)
Step 3: Calculate the total pressure in the container
1mol of ideal gas has a pressure of 1 atm
If 1 mol of PCl5 completely decomposes into 1 mol PCl3 and 1 mol Cl2
Then the pressure for 1 mol PCl3 and 1 mol Cl2 is for both 1 atm
The total pressure would be 2*1 atm = 2 atm
The total pressure in the container is 2 atm
The mass of 1.72 mol of magnesium fluoride is 107 grams.
To determine the mass of 1.72 mol of magnesium fluoride, we first need the chemical formula of magnesium fluoride. Magnesium forms a +2 ion (Mg+2) and fluoride forms a -1 ion (F-1). Since all compounds formed from ions have to be electrically neutral, we need 2 fluoride ions and 1 magnesium ion. Therefore, the formula for magnesium fluoride is MgF2.
Now we need to determine the molar mass of the compound from the molar mass values from the periodic table. Let's use a table to calculate this molar mass.
Molar mass of MgF2
Element Molar Mass (g/mol) Quantity Total (g/mol)
Mg 24.31 1 24.31
F 19.00 2 38.00
Total molar mass of MgF2 = 24.31 g/mol + 38.00 g/mol = 62.31 g/mol
This is the mass of one mole of the substance. If we have 1.72 mols of it, we multiply 1.72 by 62.31.
1.72 mol (62.31 g/mol) = 107 grams
We rounded to 107 to keep the correct number of significant digits in our answer.
