Any type of wetland that has been developed or maintained by humans for uses such as aquaculture, irrigation, or water storage.
<h3>What is a human-made wetland ?</h3>
Any kind of wetland that has been created or kept up by people for purposes like water storage, irrigation, or aquaculture.
In India's Punjab state, in the Kapurthala district, lies the man-made Kanji Wetland, which includes the Kanji Lake.
In order to give irrigation facilities to the hinterland, it was built by building the headworks over the perennial Bien River, a tributary of the Beas River.
The Sunderbans are India's biggest wetland. The world's biggest mangrove forest includes Sunderban Wetland.
Hence, the human-made wetland is an artificial wetland.
To learn more about the human-made wetland refer;
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Answer:
2. depends on both the wavelength and frequency of light.
Explanation: Speed of light(v)=wavelength×Frequency.
∴speed of light depends on both wavelength and frequency as shown from the equation above.
Answer:
Fgparallel = 170N
Explanation:
Acting down the incline would be the paralell force. The Force of gravity on an incline for the parallel portion is mgsinθ.
Fg parallel = mgsinθ
mg is 289.9, as that is the weight. θ is 35.9
Fgpar = 289.9sin35.9
Fgparallel = 170N
Answer:
See explanation
Explanation:
Notice that the condenser section includes both the hot water and space heater and station (3) is specified as being in the Quality region. Assume that 50°C is a reasonable maximum hot water temperature for home usage, thus at a high pressure of 1.6 MPa, the maximum power available for hot water heating will occur when the refrigerant at station (3) reaches the saturated liquid state. (Quick Quiz: justify this statement). Assume also that the refrigerant at station (4) reaches a subcooled liquid temperature of 20°C while heating the air.
Using the conditions shown on the diagram and assuming that station (3) is at the saturated liquid state
a) On the P-h diagram provided below carefully plot the five processes of the heat pump together with the following constant temperature lines: 50°C (hot water), 13°C (ground loop), and -10°C (outside air temperature)
b) Using the R134a property tables determine the enthalpies at all five stations and verify and indicate their values on the P-h diagram.
c) Determine the mass flow rate of the refrigerant R134a. [0.0127 kg/s]
d) Determine the power absorbed by the hot water heater [2.0 kW] and that absorbed by the space heater [0.72 kW].
e) Determine the time taken for 100 liters of water at an initial temperature of 20°C to reach the required hot water temperature of 50°C [105 minutes].
f) Determine the Coefficient of Performance of the hot water heater [COPHW = 4.0] (defined as the heat absorbed by the hot water divided by the work done on the compressor)
g) Determine the Coefficient of Performance of the heat pump [COPHP = 5.4] (defined as the total heat rejected by the refrigerant in the hot water and space heaters divided by the work done on the compressor)
h) What changes would be required of the system parameters if no geothermal water loop was used, and the evaporator was required to absorb its heat from the outside air at -10°C. Discuss the advantages of the geothermal heat pump system over other means of space and water heating
We know, For a substance they both are equal in magnitude, i.e.,
Specific Gravity = Density
Specific Gravity = 19.3 [ As Density = 19.3 ]
In short, option C would be your correct Answer!
Hope this helps!