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Andrews [41]
3 years ago
9

To meet the minimum required instrument flight experience to act as a pilot in command of an aircraft under IFR, you must have l

ogged within the preceding 6 calendar months in the same category aircraft:_______. six instrument approaches,
A) holding procedures, intercepting and tracking courses through the use of navigation systems.
B) three of which must be in the same category and class of aircraft to be flown, and 6 hours of instrument time in any aircraft.
C) and 6 hours of instrument time in any aircraft.
Physics
1 answer:
lora16 [44]3 years ago
6 0
I think its a tbh bc it seems to be the best answer out of a b c and d
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Engineers and science fiction writers have proposed designing space stations in the shape of a rotating wheel or ring, which wou
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Answer:

a. The station is rotating at 1.496 \frac{rev}{min}

b. the rotation needed is 2.8502 \frac{rev}{min}

Explanation:

We know that the centripetal acceleration is

a_{c}= \omega ^2 r

where \omega is the rotational speed and r is the radius. As the centripetal acceleration is feel like an centrifugal acceleration in the rotating frame of reference (be careful, as the rotating frame of reference is <u>NOT INERTIAL,</u> the centrifugal force is a fictitious force, the real force is the centripetal).

<h3>a. </h3>

The rotational speed  is :

2.7 \frac{m}{s^2} = \omega ^2 * 110  \ m

\omega ^2 = \frac{2.7 \frac{m}{s^2}} {110 \ m}

\omega  = \sqrt{ 0.02454 \frac{rad^2}{s^2} }

\omega  = 0.1567 \frac{rad}{s}

Knowing that there are 2\pi \ rad in a revolution and 60 seconds in a minute.

\omega  = 0.1567 \frac{rad}{s}  \frac{1 \ rev}{2\pi \ rad} \frac{60 \ s}{1 \ min}

\omega  = 1.496 \frac{rev}{min}

<h3>b. </h3>

The rotational speed needed is :

9.8 \frac{m}{s^2} = \omega ^2 * 110  \ m

\omega ^2 = \frac{9.8 \frac{m}{s^2}} {110 \ m}

\omega  = \sqrt{ 0.08909 \frac{rad^2}{s^2} }

\omega  = 0.2985 \frac{rad}{s}

Knowing that there are 2\pi \ rad in a revolution and 60 seconds in a minute.

\omega  = 0.2985 \frac{rev}{min}  \frac{1 \ rev}{2\pi \ rad} \frac{60 \ s}{1 \ min}

\omega  = 2.8502 \frac{rev}{min}

3 0
3 years ago
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Answer:

<h3>The mass of an object is the same on Earth, in orbit, or on the surface of the Moon. ... 1N=1kg ⋅m/s2. 1 N = 1 kg · m/s 2 . ... The gravitational force on a mass is its weight. ... </h3>

Explanation:

<h3>ILY:)</h3>

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