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Andrews [41]
3 years ago
9

To meet the minimum required instrument flight experience to act as a pilot in command of an aircraft under IFR, you must have l

ogged within the preceding 6 calendar months in the same category aircraft:_______. six instrument approaches,
A) holding procedures, intercepting and tracking courses through the use of navigation systems.
B) three of which must be in the same category and class of aircraft to be flown, and 6 hours of instrument time in any aircraft.
C) and 6 hours of instrument time in any aircraft.
Physics
1 answer:
lora16 [44]3 years ago
6 0
I think its a tbh bc it seems to be the best answer out of a b c and d
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I need help in physics please help me
artcher [175]

The first step is to represent the vectors shown in the image in Cartesian coordinates.

For the vector C we have a magnitude of 4.8 and an angle 22 ° with the axis -y (direction j)

To write this vector in Cartesian coordinates we must find its component in x (address i) and in the y axis.

x = 4.8sin(22)i\\\\y = 4.8cos(22)(-j)

So:

C = 4.8sin(22) i + 4.8cos(22)(-j)\\\\C = 1.798\ i - 4.450\ j

For Vector B we have a magnitude of 5.6 and an angle of 33 with the -x axis (-i direction)

So:

x = 5.6cos(33)(-i)\\\\y = 5.6 sin(33)(-j)

So:

B = 5.6cos(33)(-i) + 5.6sin(33)(-j)\\\\B = -4.696\ i - 3.05\ j

Finally the sum of B + C is made component by component in the following way:

F = (-4.696 +1.798)i + (-4.450 - 3.05)j\\\\F = -2.898\ i - 7.5\ j

Finally the magnitude of f is:

|F| = \sqrt{(-2,898)^2 + (-7.5)^2}

| F | = 8.04

3 0
3 years ago
Cross-training employees is only necessary in the genetic science industry.<br> O True<br> O False
zhannawk [14.2K]

Answer: False

Explanation:  

8 0
3 years ago
Read 2 more answers
If the distance between two charged particles is doubled, the force between them changes by a factor of ___. (1 point)
MatroZZZ [7]

Answer:

decreases 1/4 of the original value

4 0
3 years ago
A long cylindrical capacitor is made of a central wire of radius a = 2.50 mm surrounded by a conducting shell of radius b = 7.50
asambeis [7]

Answer:

The capacitance per unit length is 5.06\times10^{-11}\ F/m

(b) is correct option.

Explanation:

Given that,

Radius a= 2.50 mm

Radius b=7.50 mm

Dielectric constant = 3.68

Potential difference = 120 V

We need to calculate charge per length for the capacitance

Using formula of charge per length

\lambda=\dfrac{4\pi\epsilon_{0}\Delta V}{2 ln(\dfrac{r_{2}}{r_{1}})}

Put the value into the formula

\lambda=\dfrac{120}{9\times10^{9}\times2 ln(\dfrac{7.50\times10^{-3}}{2.50\times10^{-3}})}

\lambda=6.068\times10^{-9}\ C/m

We know that,

\lambda=\dfrac{Q}{L}

We need to calculate the capacitance per unit length

Using formula of capacitance per unit length

C=\dfrac{\dfrac{Q}{L}}{\Delta V}

C=\dfrac{6.068\times10^{-9}}{120}

C=5.06\times10^{-11}\ F/m

Hence, The capacitance per unit length is 5.06\times10^{-11}\ F/m

7 0
3 years ago
How much kinetic energy does an object have that is moving at a rate of 30 m/s and has a mass of 4000 kg ?
DaniilM [7]

Answer:

K = 1800 kJ

Explanation:

Given that,

The speed of the object, v = 30 m/s

Mass of the object, m = 4000 kg

We need to find the kinetic energy of the object. The formula for the kinetic energy is given by :

K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 4000\times 30^2\\\\K=1800000\\\\or\\\\K=1800\ kJ

So, the required kinetic energy is equal to 1800 kJ.

3 0
3 years ago
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