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Angelina_Jolie [31]
2 years ago
6

A 1000 kg race car rounds a curve with a radius of 50 m.

Physics
1 answer:
Kruka [31]2 years ago
5 0

Answer:

5644556677888777766554433

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As the wavelength increases, the frequency (2 points) decreases and energy decreases. increases and energy increases. decreases
frozen [14]
Bohr's equation for the change in energy is
\Delta E= \frac{hc}{\lambda}
where
h = Planck's constant
c == the velocity of light
λ = wavelength.

The velocity is related to wavelength and frequency, f, by
c = fλ

Let us examine the given answers on the basis of the given equations.

a. As λ increases, f decreases and ΔE decreases.
     TRUE

b. As λ increases, f increases and ΔE increases.
    FALSE

c. As λ increases, f increases and ΔE decreases.
    FALSE

Answer: 
As the wavelength increases, the frequency decreases and energy decreases.

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3 years ago
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During intercourse, Lydia constantly worries whether her partner thinks she is
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Answer is c spectatoring
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Biotic factors are the blank and blank part of the ecosystem
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Abiotic factors are the nonliving physical and chemical components of an ecosystem, while biotic factors are the living components of an ecosystem. Both types of factors affect reproduction and survival

3 0
3 years ago
Ted Clubber Lang. A hook in boxing primarily involves horizontal flexion of the shoulder while maintaining a constant angle at t
il63 [147K]

Answer:

15 m/s or 1500 cm/s

Explanation:

Given that

Speed of the shoulder, v(h) = 75 cm/s = 0.75 m/s

Distance moved during the hook, d(h) = 5 cm = 0.05 m

Distance moved by the fist, d(f) = 100 cm = 1 m

Average speed of the fist during the hook, v(f) = ? cm/s = m/s

This can be solved by a very simple relation.

d(f) / d(h) = v(f) / v(h)

v(f) = [d(f) * v(h)] / d(h)

v(f) = (1 * 0.75) / 0.05

v(f) = 0.75 / 0.05

v(f) = 15 m/s

Therefore, the average speed of the fist during the hook is 15 m/s or 1500 cm/s

6 0
3 years ago
PLSSS HELP MEEEE
vekshin1

Answer:

Cu2+

Explanation:

7 0
3 years ago
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