Two angles are said to be complementary, if the sum of the measures of the to angles is equal to 90 degrees.
Thus, given that HFG is complementary to ACB, them mHFG + mACB = 90 degrees.
From the figure, given that the line from point F meats line CE at point P, then HFG = CFP.
But mCFE = 90 degrees and mCFE = mCFP + mPFE
Also PFE = DFH
Thus, mCFE = mCFP + mPFE = mHFG + mDFH = 90 degrees
Recall that mHFG + mACB = 90 degrees
Thus, mHFG + mACB = mHFG + mDFH
Therefore, mACB = mDFH.
To solve the inequality 

The numerator
is not factorizable.
so factor the denominator
:

Now take 
Then we get factor of the denominator as 
Thus 
Now 
Signs of 

is the required solution of the given inequality.
Answer:
a,c,d
Step-by-step explanation:
To find the Chebyshev's inequality, P | Xn - E(X)| <= δ/4 >= 1 - (δ^2/25)/(δ^2/16) = 1 - (16/25) = 9/25 = 0.36
The answer in this question which is the probability that the average of the physicist's measurement is within δ/4 units of the actual specific gravity is at least 0.36%
Answer:
1: 80 (Vertical angles congruent)
2: 70 (Vertical angles congruent)
3:
4: 110 (Straight angle w/ angle 2, 180-70 {known variable})
5: 90 (Right angle)
6: 90 (Right angle)
7: 20 (180-90-70 (unmarked angle opposite 4)
9:
10: