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Vlada [557]
3 years ago
10

Lee's muffin mix calls for 2/3 cup of milk, 1/3 Cup of oil and 1/3 cup of sugar.Hos more milk than oil does she need for the muf

fin mix
Mathematics
1 answer:
marysya [2.9K]3 years ago
5 0
You has some spelling errors, im guessing this is what you ment : 

<span>Lee's muffin mix calls for 2/3 cup of milk, 1/3 Cup of oil and 1/3 cup of sugar. How much more milk than oil does she need for the muffin mix

</span><span>Answer : She needs 1/3 cup more milk than oil

to figure this out do 2/3 - 1/3 = 1/3</span>
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Solve for w.<br> - 2w – 14= 2(w+1)<br> Simplify your answer as much
snow_tiger [21]

Answer:

w = -4

Step-by-step explanation:

<u>Step 1:  Distribute</u>

-2w - 14 = 2(w + 1)

-2w - 14 = 2w + 2

<u>Step 2:  Add 2w to both sides</u>

-2w - 14 + 2w = 2w + 2 + 2w

-14 = 4w + 2

<u>Step 3:  Subtract 2 from both sides</u>

-14 - 2 = 4w + 2 - 2

-16 = 4w

<u>Step 4:  Divide both sides by 4</u>

-16 / 4 = 4w / 4

<em>-4 = w</em>

<em />

Answer:  w = -4

7 0
3 years ago
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Suppose a projectile is fired from a cannon with velocity v0 and angle of elevation θ. The horizontal distance Rθ it travels (in
jolli1 [7]

Answer:

0.25 rad to the nearest hundredth radian

Step-by-step explanation:

Here is the complete question

Suppose a projectile is fired from a cannon with velocity vo and angle of elevation (theta). The horizontal distance R(θ) it travels (in feet) is given by the following.  

R(θ) = v₀²sin2θ/32

If vo=80ft/s what angel (theta) (in radians) should be used to hit a target on the ground 95 feet in front of the cannon?

Do not round any intermediate computations, and round your answer(s) to the nearest hundredth of a radian.

(θ)= ?rad

Solution

R(θ) = v₀²sin2θ/32

If v₀ = 80 ft/s and R(θ) = 95 ft

θ = [sin⁻¹(32R(θ)/v₀²)]/2

= [sin⁻¹(32 × 95/80²)]/2

=  [sin⁻¹(3040/6400)]/2

=  [sin⁻¹(0.475)]/2

= 28.36°/2

= 14.18°

Converting 14.18° to radians, we have 14.18° × π/180° = 0.2475 rad

= 0.25 rad to the nearest hundredth radian

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3 years ago
A truck driver is 2 hours into 1,346-Mile drive and has driven 125 Miles s far. Which of the following is the number of miles th
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The answer is 1,121 miles
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3 years ago
A popular resort hotel has 300 rooms and is usually fully booked. About 7% of the time a reservation is canceled before the 6:00
kicyunya [14]

Answer:

8.69% probability that at least 285 rooms will be occupied.

Step-by-step explanation:

For each booked hotel room, there are only two possible outcomes. Either there is a cancelation, or there is not. So we use concepts of the binomial probability distribution to solve this question.

However, we are working with a big sample. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

A popular resort hotel has 300 rooms and is usually fully booked. This means that n = 300

About 7% of the time a reservation is canceled before the 6:00 p.m. deadline with no pen-alty. What is the probability that at least 285 rooms will be occupied?

Here a success is a reservation not being canceled. There is a 7% probability that a reservation is canceled, and a 100 - 7 = 93% probability that a reservation is not canceled, that is, a room is occupied.  So we use p = 0.93

Approximating the binomial to the normal.

E(X) = np = 300*0.93 = 279

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{300*0.93*0.07} = 4.42

The probability that at least 285 rooms will be occupied is 1 subtracted by the pvalue of Z when X = 285. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{285- 279}{4.42}

Z = 1.36

Z = 1.36 has a pvalue of 0.9131.

So there is a 1-0.9131 = 0.0869 = 8.69% probability that at least 285 rooms will be occupied.

8 0
3 years ago
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bearhunter [10]

Answer:

12

Step-by-step explanation:

count to 69 and you got 12 lay ups

5 0
3 years ago
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