1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
goblinko [34]
3 years ago
13

A pool player hit a ball with a mass of 0.25kg. The ball travels at a velocity of 15 m/s for 0.75 s until it hits the side of th

e pool table.
What additional information is required to determine the ball's weight?

A.
the force of inertia acting on the pool cue

B.
the displacement of the pool ball

C.
the value in m/s² of gravity acting on the pool ball

D.
the distance to the nearest pocket in the table
Physics
1 answer:
ohaa [14]3 years ago
6 0

Assuming that the pool hall is located somewhere on Earth,
you don't need any additional information.  In fact, you already
have more than you need.

              Weight = (mass) times (acceleration of gravity) .

The question tells you the mass of the ball, and everybody
knows that the acceleration of gravity on Earth is  9.8 m/s² .
So the weight of the ball is

       (0.25 kg) x (9.8 m/s²)  =  2.45 newtons.

I suppose if you momentarily forgot the acceleration of gravity,
then you'd need somebody to remind you, and that would be
choice 'C', but it would not have to be in m/s².  It could be in
any convenient units of acceleration, and you could easily
convert it to  m/s²  before doing the calculation.

You might be interested in
A 61.0-kg person jumps from rest off a 10.0-m-high tower straight down into the water. Neglect air resistance. She comes to rest
9966 [12]

Answer:

Explanation:

In this case, law of conservation of energy will be implemented. It states that "the energy of the system remains conserved until or unless some external force act on it. Energy of the system may went through the conversion process like kinetic energy into potential and potential into kinetic energy.But their total always remain the same in conserved systems."

Given data:

Height of tower = 10.0 m

Depth of the pool = 3.00 cm

Mass of person = 61.0 kg

Solution:

Initial energy = Final energy

U_{i} =  (K.E) + U_{f}

As the person was at height initially so it has the potential energy only.

mg(h_{1} +h_{2}) = K.E + mgh_{2}

K.E = mgh_{1}

K.E = (61.0)(9.8)(10)\\K.E = 5978 J

Lets find out the magnitude of the force that the water is exerting on the diver.

W =ΔK.E

F.h_{2} = 5978\\

F = \frac{5978}{3}

F = 1992.67 N

7 0
3 years ago
A boy finds an abandoned mine shaft in the woods, and wants to know how deep the hole is. He drops in a stone, and counts 4 seco
oee [108]
S=(0x4)+(0.5x4.81x4x4)
S=0.78.48

The depth is approximately 78 meters.
(My brain hurts now) :P Good Luck!
4 0
3 years ago
emperature is most closely related to which property of a liquid? (1 point) Select one: a. the volume of the liquid b. the numbe
Rainbow [258]

Answer

b. the number of atoms in each molecule.

Explanation:

5 0
3 years ago
The presence of which phenomenon proved the predictability of the big bang theory?
Law Incorporation [45]
The measurement of the expansion of the universe was what gave rise to the big bang theory and it's predictions. 
7 0
2 years ago
Read 2 more answers
Q11) If you were standing at the top of a building and you dropped a rock.
Dafna1 [17]

Answer:

Part A

The distance travel by the rock is approximately 132.496 m

Part B

The speed when the rock hits the ground is approximately 50.96 m/s

Explanation:

Part A

The question is focused on the kinetics equation of a free falling object

The given parameter is the time it takes the rock to hit the ground, t = 5.2 s

For an object in free fall, we have;

h = 1/2·g·t²

Where;

h = The height from which the object is dropped

g = The acceleration due to gravity ≈ 9.8 m/s²

t = The time taken to travel the distance, h = 5.2 s

∴ h = 1/2 × 9.8 m/s² × (5.2 s)² ≈ 132.496 m

The distance travel by the rock, h ≈ 132.496 m

Part B

The speed, 'v', when the rock hits the ground, is given by the following kinematic equation,

v = g·t

∴ v = 9.8 m/s² × 5.2 s = 50.96 m/s

The speed when the rock hits the ground, v ≈ 50.96 m/s.

8 0
2 years ago
Other questions:
  • The magnetic field produced by the solenoid in a magnetic resonance imaging (MRI) system designed for measurements on whole huma
    14·2 answers
  • A child in a boat throws a 5.10-kg package out horizontally with a speed of 10.0 m/s. the mass of the child is 27.6 kg and the m
    9·1 answer
  • How do you calculate energie
    6·2 answers
  • Which statement is true about a farsighted (hyperopic) eye?
    12·1 answer
  • Which often results from great variations in a habitat’s abiotic conditions?
    9·2 answers
  • In the javelin throw at a track-and-field event, the javelin is launched at a speed of 29 m/s at an angle of 36???? above the ho
    6·1 answer
  • What is the average speed in miles per hour of the car that traveled a total of 200 miles in 5.5 hours
    13·2 answers
  • A snail is at the bottom of a well, 115 feet deep. On day 1, it starts climbing up the side. That night it rests and slips down
    11·1 answer
  • The urethra extends from the:
    5·1 answer
  • Starting over, so here's some points! Take em<br> ~Jayden
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!