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goblinko [34]
3 years ago
13

A pool player hit a ball with a mass of 0.25kg. The ball travels at a velocity of 15 m/s for 0.75 s until it hits the side of th

e pool table.
What additional information is required to determine the ball's weight?

A.
the force of inertia acting on the pool cue

B.
the displacement of the pool ball

C.
the value in m/s² of gravity acting on the pool ball

D.
the distance to the nearest pocket in the table
Physics
1 answer:
ohaa [14]3 years ago
6 0

Assuming that the pool hall is located somewhere on Earth,
you don't need any additional information.  In fact, you already
have more than you need.

              Weight = (mass) times (acceleration of gravity) .

The question tells you the mass of the ball, and everybody
knows that the acceleration of gravity on Earth is  9.8 m/s² .
So the weight of the ball is

       (0.25 kg) x (9.8 m/s²)  =  2.45 newtons.

I suppose if you momentarily forgot the acceleration of gravity,
then you'd need somebody to remind you, and that would be
choice 'C', but it would not have to be in m/s².  It could be in
any convenient units of acceleration, and you could easily
convert it to  m/s²  before doing the calculation.

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How does the atmospheric temperature and size of inner planets compare with those of outer planets?
amid [387]
The inner planets are rocky and have diameters of less than 13,000 kilometers. The outer planets include Jupiter, Saturn, Uranus, and Neptune. The smaller, inner planets include Mercury, Venus, Earth, and Mars. Inner planet's atmosphere is thin. (Mercury has no atmosphere). Outer Planets: Outer planets' atmosphere is very thick. The four inner planets, Mercury, Venus, Earth, and Mars, are warmer than the outer gas giants. However, the temperature of the planets does not follow a linear path from the Sun.

Hope this helps!
Please give Brainliest!
6 0
2 years ago
Select the appropriate units for each property of a wave.
IceJOKER [234]

Intensity: Decibels

Amplitude: Meters

Frequency: Hertz

<u>Explanation:</u>

The Wave is not visible to eyes and they can easily propagate through vacuum. the average power travelling at a given period of time in a space is the intensity. Decibels is the measure of intensity. it is measured in the decibel scale. The wave's strength and the intensity gives the amplitude of wave. It is measured using meters.

The wave's amplitude and the energy has a direct proportionality.  The number occurrence of wave cycles per second refers to the frequency of wave. it is measured in hertz. it is also measured as the number of cycles that occurs per second.

4 0
2 years ago
The data indicate the populations of mammals in the Florida Everglades in different years over the past two decades. The Burmese
soldier1979 [14.2K]

Answer:

C) Burmese pythons lack natural predators and can utilize a wide variety of food sources in the Everglades.

Explanation:

Due to it being an invasive specie (naturally found in South Asia), and also one of the five largest species of snakes in the world, the Burmese pythons lack natural predators in this new territories.

The Burmese viper is also an opportunistic hunter and would eat anything it can overpower, it easily made a wide range of food varieties in these swamps.

8 0
3 years ago
car traveling on a flat (unbanked), circular track accelerates uniformly from rest with a tangential acceleration of a. The car
Luba_88 [7]

Answer:

0.572

Explanation:

First examine the force of friction at the slipping point where Ff = µsFN = µsmg.

the mass of the car is unknown,

The only force on the car that is not completely in the vertical direction is friction, so let us consider the sums of forces in the tangential and centerward directions.

First the tangential direction

∑Ft =Fft =mat

And then in the centerward direction ∑Fc =Ffc =mac =mv²t/r

Going back to our constant acceleration equations we see that v²t = v²ti +2at∆x = 2at πr/2

So going backwards and plugging in Ffc =m2atπr/ 2r =πmat

Ff = √(F2ft +F2fc)= matp √(1+π²)

µs = Ff /mg = at /g √(1+π²)=

1.70m/s/2 9.80 m/s² x√(1+π²)= 0.572

7 0
3 years ago
Billy drops a water balloon from the roof of his house. Since the balloon began with an original velocity of zero how far above
VashaNatasha [74]
T=2,5s
a=g≈10m/s²

h=s=?

s= \frac{1}{2} at^2 \Leftrightarrow h=\frac{1}{2}gt^2=\frac{1}{2}*10m/s^2 *(2,5s)^2=5m/s^2* \frac{25}{4} s^2=\boxed{31,25m}



"Non nobis, Domine, non nobis, sed Nomini tuo da gloriam."


Regards M.Y.
7 0
3 years ago
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