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goblinko [34]
4 years ago
13

A pool player hit a ball with a mass of 0.25kg. The ball travels at a velocity of 15 m/s for 0.75 s until it hits the side of th

e pool table.
What additional information is required to determine the ball's weight?

A.
the force of inertia acting on the pool cue

B.
the displacement of the pool ball

C.
the value in m/s² of gravity acting on the pool ball

D.
the distance to the nearest pocket in the table
Physics
1 answer:
ohaa [14]4 years ago
6 0

Assuming that the pool hall is located somewhere on Earth,
you don't need any additional information.  In fact, you already
have more than you need.

              Weight = (mass) times (acceleration of gravity) .

The question tells you the mass of the ball, and everybody
knows that the acceleration of gravity on Earth is  9.8 m/s² .
So the weight of the ball is

       (0.25 kg) x (9.8 m/s²)  =  2.45 newtons.

I suppose if you momentarily forgot the acceleration of gravity,
then you'd need somebody to remind you, and that would be
choice 'C', but it would not have to be in m/s².  It could be in
any convenient units of acceleration, and you could easily
convert it to  m/s²  before doing the calculation.

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ElenaW [278]

Answer:

The answer to your question is a = 1.3 m/s²

Explanation:

Centripetal acceleration is the motion of a body that transverse a circular path.

Data

mass = 7 kg

radius = r = 1.3 m

angular rate = w = 1.0 rev/s

centripetal acceleration = a = ?

Formula

a = rw²

Substitution

a = (1.3)(1)²

Simplification and result

a = 1.3 m/s²

4 0
3 years ago
a car takes off from rest and covers a distance of 80m on a straight road in 10s.calculate the magnitude of its acceleration
olasank [31]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

Here's the solution :

Let's find the final velocity :

  • \dfrac{displacement}{time}

  • \dfrac{80}{10}

  • 8 \:  \: ms {}^{ - 1}

Initial velocity (u) = 0 (cuz it started from rest)

Final velocity (v) = 8 m/s

Time taken (t) = 10 sec

now, we know that :

  • acceleration =  \dfrac{v - u}{t}

  • \dfrac{8 - 0}{10}

  • \dfrac{8}{10}

  • 0.8 \:  \: m {s}^{ - 2}

Acceleration = 0.8 m/s²

7 0
3 years ago
A "biconvex" lens is one in which both surfaces of the lens bulge outwards. Suppose you had a biconvex lens with radii of curvat
madam [21]

Answer:

12 cm

Explanation:

We shall use Lens makers formula here which is as follows

\frac{1}{F} =(\mu-1) (\frac{1}{R_1} -\frac{1}{R_2})

Put μ = 1.5 , R₁ = 10 cm ,R₂ = -  15 cm ( according to sign convention )

\frac{1}{F} =(1.5-1) (\frac{1}{10} -\frac{1}{-15})

= .5 x ( 15 + 10 ) / 15 x 10

= \frac{25}{2\times10\times15}

F = 12 cm

7 0
3 years ago
A horizontal line on a distance-time graph means the object is
IgorLugansk [536]
At rest because if the distance is not changing, then it is not moving any further, so it must not be moving! The time keeps going no matter what, so the distance, whether it is 0 m or 10,000 km, if the y is horizontal the distance does not change. 
6 0
4 years ago
A 10 kg box accelerates for at a rate of 12 miles per second what is the force acting on the box
lions [1.4K]

193080N

Explanation:

Given parameters:

Mass of the box = 10kg

Acceleration = 12miles per second

Unknown:

Force on the box = ?

Solution:

The force acting on the box is function of the mass and acceleration of the box.

  Force = mass x acceleration

   Now we need to convert the given acceleration to m/s

     1000m = 1km

      1.609km = 1miles

    \frac{12 miles }{seconds } x \frac{1.609km}{1miles} x \frac{1000}{1km}

      = 19308m/s

 Force on box = 10 x 19308 = 193080N

Learn more:

Force problems brainly.com/question/4033012

#learnwithBrainly

7 0
3 years ago
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