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vivado [14]
3 years ago
12

Light bulb 1 operates with a filament temperature of 2800 K, whereas light bulb 2 has a filament temperature of 1700 K. Both fil

aments have the same emissivity, and both bulbs radiate the same power. Find the ratio A1/A2 of the filament areas of the bulbs. A1/A2
Physics
1 answer:
Veronika [31]3 years ago
5 0

Answer:

A₁/A₂ = 0.136

Explanation:

The power radiated by a filament bulb is given by the following formula:

E = σεAT⁴

where,

E = Emissive Power

σ = Stephen Boltzman Constant

ε = emissivity

A = Area

T = Absolute Temperature

Therefore, for bulb 1:

E₁ = σε₁A₁T₁⁴

And for bulb 2:

E₂ = σε₂A₂T₂⁴

Dividing both the equations:

E₁/E₂ = σε₁A₁T₁⁴/σε₂A₂T₂⁴

According to given condition, the emissive power and the emissivity is same for both the bulbs. Therefore,

E/E = σεA₁T₁⁴/σεA₂T₂⁴

1 = A₁T₁⁴/A₂T₂⁴

A₁/A₂ = (T₂/T₁)⁴

where,

T₁ = 2800 K

T₂ = 1700 K

Therefore,

A₁/A₂ = (1700 K/2800 K)⁴

<u>A₁/A₂ = 0.136</u>

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A rock is thrown with a force of 500 N and an acceleration is 75 m/s^2. What is its mass?
artcher [175]

Answer:

We conclude that the mass of a rock with a force of 500 N and an acceleration of 75 m/s² is 6.7 kg.

Hence, option D is correct.

Explanation:

Given

  • Force F = 500 N
  • Acceleration a = 75 m/s²

To determine

Mass m = ?

Important Tip:

  • The mass of a rock can be found using the formula F = ma

Using the formula

F = ma

where

  • F is the force (N)
  • m is the mass (kg)
  • a is the acceleration (m/s²)

now substituting F = 500, and a = 75 m/s² in the formula

F = ma

500 = m(75)

switch sides

m\left(75\right)=500

Divide both sides by 75

\frac{m\cdot \:75}{75}=\frac{500}{75}

simplify

m=\frac{20}{3}

m=6.7 kg

Therefore, we conclude that the mass of a rock with a force of 500 N and an acceleration of 75 m/s² is 6.7 kg.

Hence, option D is correct.

7 0
3 years ago
A 328-kg car moving at 19.1 m/s in the + x direction hits from behind a second car moving at 13.0 m/s in the same direction. If
Kisachek [45]

Answer:

+14.0 m/s

Explanation:

we have mV + Mv = mU + Mu we solve for U = (mV + Mv - Mu)/m = (328*19.1 + 790*13 - 790*15.1)/328 = 14. Answer

8 0
3 years ago
4. An object is moving with an initial velocity of 9 m/s. It accelerates at a rate of 1.5
Mazyrski [523]

Answer:

11.87 ms⁻¹

Explanation:

You can use the kinematic equation

v² = u² + 2as

Where v = final velocity

          u = initial velocity

          a = acceleration

          s = displacement

v² = 9² + 2×1.5×20

So you get v = 11.87 ms⁻¹

7 0
3 years ago
A certain elevator cab has a total run of 198 m and a maximum speed is 317 m/min, and it accelerates from rest and then back to
tester [92]

Answer:

Explanation:

Given

Total run=198 m

maximum speed=317 m/min=5.28 m/s

acceleration=1.11 m/s^2

(a)Distance traveled while  accelerating

v^2-u^2=2as

(5.28)^2-0=2\times 1.11\times s

s=12.57 m

time taken

v=u+at

5.28=0+1.11\times t

t=4.75 s

(b)Time taken to cover 198 m

if car takes 12.57 m & 4.75 s to reach max speed so it also takes 12.57 m and 4.75 s to stop from max speed

Distance traveled with max speed=198-25.14=172.86 m

time taken=\frac{172.86}{5.28}=32.73 s

total time=4.75+32.73+4.75=42.25 s

7 0
3 years ago
What will the distance from the point of origin if a car traveled at a speed of 25 km/hr for a time of 1 hour and 15 minutes?
liberstina [14]
Distance = velocity * time

1 hour and 15 minutes = 1.25 hours

25km/hr * 1.25 hours = 31.25km
6 0
3 years ago
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