1. What is an equation of a line, in point-slope form, that passes through (1,-7) and has a slope of -2/3?
Point Slope form y − y1 = m(x − x1)
Y1: -7 x1:1 slope :-2/3
Y-(-7)=-2/3(x-1)
Y+7=-2/3(x-1)
2. What is the equation of a line, in point-slope form, that passes through (-2,-6) and had a slope of 1/3?
Y-(-6)=1/3(x-(-2))
Y+6=1/3(x+2)
3.What is an equation in point-slope form of the line that passes through the points (4,5) and (-3,-1)
SlopeM: =change in y/change in x
M= -1-5/-3-4
M= -6/-7
M=6/7
So now slope:6/7, point (4,5)
Y-y1=m(x-x1)
Equation in point slope
Y-5=6/7(x-4)
A = 9 (Sorry I can't do the other ones, I haven't learned those ones yet) Hope this helps!! :P
Answer:
Step-by-step explanation: I would say y=x+2 or 2 because every number that you add 2 to, it gives you the solution which is the second number
Hope this helps!!!!
Please mark Brainliest!!!!!☺
Hello, please consider the following.
We will multiply the numerator and denominator by
to get rid of the root in the denominator.
First of all, we cannot divide by 0, right? So, we need to make sure that the denominator is different from 0.
We need to take any x real number different from 8/3 then and simplify the expression.
Let's do it!
Thank you
Answer:
y = 18 / (x + 2)²
Step-by-step explanation:
Inversely proportional
y * (x + 2)² = k
when x=1, y=2
k = 2 * (1 + 2)²
k = 18
-----------------------
y * (x + 2)² = 18
Divide both sides by (x + 2)²
y = 18 / (x + 2)²
