we are given point as
(x,y)=(5,7)
translating 3 units to right side
It means we will subtract 3 to x-value
and we get
(x,y)= (5-3,7)
(x,y)=(2,7)
now, it is reflected about x-axis
so, we can change y-value as -y
so, we get our new point as
(x,y)=(2,-7)
now, we have to find it's image reflection
so, we will get
(x',y')=(-7,2).........Answer
0.442
Step-by-step explanation:
Step 1 :
Given that 11% of the lights are defective.
So probability of a light randomly chosen is defective is .11
This implies probability of a light randomly chosen is not defective is 1 - .11 = .89
Step 2 :
In a pack of 5 light bulbs the probability that none of them are defective is (0.89)^ 5
Hence the probability that at least one of the light bulbs is defective is
1-(0.89)^ 5 = 1 - 0.558 = 0.442
Answer:
5 1/6
Step-by-step explanation:
Note that - ( -7 1/3) = 7 1/3. The two ' - ' signs cancel each other.
Thus, the original expression becomes -2 1/6 + 7 1/3.
Here the LCD is 6. We re-write the above expression as -2 1/6 + 7 2/6.
Reversing the order of these terms makes the work a bit easier.
7 2/6 - 2 1/6 comes out to 5 1/6
<span>P(4, -4) ----> (-4, 7)
x- axis from 4 to -4 ; move to the left 8 units.
y-axis from -4 to 7 ; move up 11 units
</span><span>D. left 8; up 11
</span><span>C(3, -1) translated to the left 4 units and up 1 unit.
from 3 of x-axis move to the left 4 units to arrive at -1
from -1 of y-axis move up 1 unit is to arrive at 0.
(xy) </span>→ (x-4, y + 1) (-1,0) Choice D.
