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Zolol [24]
4 years ago
14

Solve for x in the equation 3x^2-18x+5=47

Mathematics
2 answers:
boyakko [2]4 years ago
8 0
x = 3+- \sqrt{23}
evablogger [386]4 years ago
3 0

Answer:

x≅7.80,-1.80 (rounded to 2 decimal places)


Step-by-step explanation:

This is a quadratic equation : 3x^2-18x+5=47

Bringing everything to left side:

3x^2-18x+5=47\\3x^2-18x+5-47=0\\3x^2-18x-42=0


We can use the quadratic formula to find the value(s) of x:

<u>Quadratic Formula</u>:

  • x=\frac{-b+\sqrt{b^2-4ac} }{2a}

and

  • x=\frac{-b-\sqrt{b^2-4ac} }{2a}

Where,

  • a is the coefficient of x^2
  • b is the coefficient of x
  • c is the constant term

For our question we have:

a=3\\b=-18\\c=-42

<em>Plugging in all the values we get:</em>

x=\frac{-(-18)+\sqrt{(-18)^2-4(3)(-42)} }{2(3)}\\x=\frac{18+\sqrt{828} }{6}

This is approximately 7.80

and

x=\frac{-(-18)-\sqrt{(-18)^2-4(3)(-42)} }{2(3)}\\x=\frac{18-\sqrt{828} }{6}

This is approximately -1.80


So, x≅7.80,-1.80



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