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Levart [38]
3 years ago
6

What is the value of 6X to the 3rd power when X is 5

Mathematics
2 answers:
Nat2105 [25]3 years ago
6 0

Hello from MrBillDoesMath!

Answer:

27000

Discussion:

( 6x) ^ 3 =

(6*6*6) * (x*x*x) =

216       * x^3

When x =5  this equals

216 * 5^3 =

216 * 125 =

27000



Thank you,

MrB

faltersainse [42]3 years ago
5 0
So you’re saying f(x)=6x^3

Insert the values
f(5)=6(5)^3

Order of operations
5 to the 3rd power is 125

f(5)=6(125)

6 x 125 =750

Therefore

f(5) = 750
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A sealed tank of water measures 10cm x 8 cm x 40cm. When it stands on one
Pavel [41]

Answer:

New height = 6

Step-by-step explanation:

The water is going to be the same volume no matter how the tank is orientated.

So you can do this 2 ways.

First way

Find the volume in the tank when the water goes up 24 cm on the height.

V = L*W*h

L = 8

W = 10

H = 24

V = 1920 cm^3

Now do it using the

L = 40

W = 8

h = ?

1920 = L * W * h

1920 = 40 * 8 * h

1920 = 320 * h

h * 320 = 1920

h = 1920/320

h = 6

Or you can do it without finding the 1920

L*W*h = L1 * w1 * h1

8*10*24 = 40 * 8 * h                                The 8's cancel

10*24 = 40*h                                           Divide both sides by 10

24 = 4h                                                    Divide by 4

h = 6

Same as you got before.

7 0
3 years ago
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14.       1.5, 10    <- Answer
15.       5,1          <- Answer

Proof 14 

Solve the following system:
{2 x - y = -7 | (equation 1)
4 x - y = -4 | (equation 2)
Swap equation 1 with equation 2:
{4 x - y = -4 | (equation 1)
2 x - y = -7 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{4 x - y = -4 | (equation 1)
0 x - y/2 = -5 | (equation 2)
Multiply equation 2 by -2:
{4 x - y = -4 | (equation 1)
0 x+y = 10 | (equation 2)
Add equation 2 to equation 1:
{4 x+0 y = 6 | (equation 1)
0 x+y = 10 | (equation 2)
Divide equation 1 by 4:
{x+0 y = 3/2 | (equation 1)
0 x+y = 10 | (equation 2)
Collect results:
Answer: {x = 1.5               
                y = 10

Proof 15. 

Solve the following system:
{5 x + 7 y = 32 | (equation 1)
8 x + 6 y = 46 | (equation 2)
Swap equation 1 with equation 2:
{8 x + 6 y = 46 | (equation 1)
5 x + 7 y = 32 | (equation 2)
Subtract 5/8 × (equation 1) from equation 2:{8 x + 6 y = 46 | (equation 1)
0 x+(13 y)/4 = 13/4 | (equation 2)
Divide equation 1 by 2:
{4 x + 3 y = 23 | (equation 1)
0 x+(13 y)/4 = 13/4 | (equation 2)
Multiply equation 2 by 4/13:
{4 x + 3 y = 23 | (equation 1)
0 x+y = 1 | (equation 2)
Subtract 3 × (equation 2) from equation 1:
{4 x+0 y = 20 | (equation 1)
0 x+y = 1 | (equation 2)
Divide equation 1 by 4:
{x+0 y = 5 | (equation 1)
0 x+y = 1 | (equation 2)
Collect results:
Answer:  {x = 5                           y = 1
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Answer:

Step-by-step explanation:

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