Which activity would contribute the most to water pollution?

A 48.3 mL sample of gas in a cylinder is warmed from 22 C, 87 C to 0.0 C what is the final temperature

snow_lady [41]

The answer is:

the volume stays the same. it is the pressure that increases

7 0

3 years ago

Gaseous ethane (CH,CH,) will react with gaseous oxygen (0,) to produce gaseous carbon dioxide (CO) and gaseous water (H2O). Supp

notka56 [123]

Answer:

0.00 g

Explanation:

We have the masses of two reactants, so this is a limiting reactant problem.

We will need a balanced equation with masses, moles, and molar masses of the compounds involved.

1. Gather all the information in one place with molar masses above the formulas and masses below them.

Mᵣ 30.07 32.00

2CH₃CH₃ + 7O₂ ⟶ 4CO₂ + 6H₂O

Mass/g: 1.50 11.

2. Calculate the moles of each reactant

$\text{moles of C$_{2}$H}_{6} = \text{1.50 g C$_{2}$H}_{6} \times \dfrac{\text{1 mol C$_{2}$H}_{6}}{\text{30.07 g C$_{2}$H}_{6}} = \text{0.04988 mol C$_{2}$H}_{6}\\\\\text{moles of O}_{2} = \text{11. g O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{32.00 g O}_{2}} = \text{0.34 mol O}_{2}$

3. Calculate the moles of CO₂ we can obtain from each reactant

From ethane:

The molar ratio is 4 mol CO₂:2 mol C₂H₆

$\text{Moles of CO}_{2} = \text{0.04988 mol C$_{2}$H}_{6} \times \dfrac{\text{4 mol CO}_{2}}{\text{2 mol C$_{2}$H}_{6}} = \text{0.09976 mol CO}_{2}$

From oxygen:

The molar ratio is 4 mol CO₂:7 mol O₂

$\text{Moles of CO}_{2} = \text{0.34 mol O}_{2}\times \dfrac{\text{4 mol CO}_{2}}{\text{7 mol O}_{2}} = \text{0.20 mol CO}_{2}$

4. Identify the limiting and excess reactants

The limiting reactant is ethane, because it gives the smaller amount of CO₂.

The excess reactant is oxygen.

5. Mass of ethane left over.

Ethane is the limiting reactant. It will be completely used up.

The mass of ethane left over will be 0.00 g.

8 0

3 years ago

For Lewis acids and bases, the base is defined as an electron pair donor / acceptor (circle the correct answer).

damaskus [11]

Answer: electron donor.

Explanation:

According to Arrhenius concept, a base is defined as a substance which donates hydroxide ions $(OH^-)$ when dissolved in water and an acid is defined as a substance which donates hydronium ions $(H_3O^+)$ in water.

According to the Bronsted Lowry conjugate acid-base theory, an acid is defined as a substance which donates protons and a base is defined as a substance which accepts protons.

According to the Lewis concept, an acid is defined as a substance that accepts electron pairs and base is defined as a substance which donates electron pairs.

$NH_3+H^+\rightarrow NH_4^+$

Here $NH_3$ acts as lewis base and $H^+$ act as lewis acid.

Thus lewis base is defined as an electron pair donor.

8 0

4 years ago

PLEASE ANSWER...........WILL MARK BRAINLIEST!!!!!!!

fomenos

Explanation:

Alkali metal cations reacts vigorously with halogens to form ionic/electrovalent compounds.

The alkali metals are about the most reactive metals and they belong to group I .
In their outermost shell, they have one valence shell electron.
Alkali metals are largely electropositive willing to release their valence electron to attain stability.
The halogens have seven electrons in their outermost shell. To complete their configuration, they need just one electron.
All the halogens are strongly electronegative and they are readily reactive.
In the vicinity of group 1 elements, they react vigorously.
This is due to the electrostatic attraction between the metal and non-metal ion formed.
Therefore, they form strong ionic bonds between their compounds.

Learn more:

sodium alkali and halogens brainly.com/question/6324347

#learnwithBrainly

4 0

4 years ago

Read 2 more answers

Help me answer the questions in the photo i am very confused

AlladinOne [14]

Answer:

The range is also the whole of R

Explanation:

8 0

3 years ago