You can put a known amount sodium into some sort of time release mechanism such as a pill made from soluble material. Then you can place the sodium into a calorimeter with a known mass of water and record the temperature change the water undergoes during the reaction. Then you can use the equation q(water)=m(water)c(water)ΔT to find the amount of heat absorbed by the water. since the amount of heat absorbed by the water is the amount of heat released from the sodium, q(sodium)=-q(water). Than you can use the equation q(sodium)=m(sodium)c(sodium)ΔT and solve for c(sodium)
I hope this helps and feel free to ask about anything that was unclear in the comments.
The correct answer is d) chrima
Answer:
171°F is the answer of this question
Ms ( mass of solute): 33,6g
mss (mass of solution): 33,6+192g = 225,6g
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C = ms/mss × 100%
C = 33.6/225.6 × 100%
C = 14,89% ≈ 14,9%
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