30.6 g of AgNO₃
Explanation:
We have the following chemical reaction:
Na₃PO₄ + 3 AgNO₃ → Ag₃PO₄ + 3 NaNO₃
Now we calculate the number of moles of Na₃PO₄:
number of moles = mass / molecular weight
number of moles of Na₃PO₄ = 9.44 / 164 = 0.06 moles
Now we formulate the following reasoning:
if 1 mole of Na₃PO₄ will react with 3 moles of AgNO₃
then 0.06 moles of Na₃PO₄ will react with X moles of AgNO₃
X = (0.06 × 3) / 1 = 0.18 moles of AgNO₃
mass = number of moles × molecular weight
mass of AgNO₃ = 0.18 × 170 = 30.6 g
Learn more about:
mole concept
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