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Gala2k [10]
2 years ago
7

Erica is working in the lab. She wants to remove the fine dust particles suspended in a sample of oil. Which method is she most

likely to use?
A reverse osmosis
B osmosis
C filtration
D dilution
Chemistry
2 answers:
BARSIC [14]2 years ago
7 0
Option a is right answer that is reverse osmosis.
Veseljchak [2.6K]2 years ago
4 0

The correct option is A.

Reverse osmosis is a special type of filtration, which involves the passing of a solvent through a semi permeable membrane in the direction that is opposite to that of natural osmosis. Pressure is always used in this process to enforce separation. The method is usually used to remove ions, fine dust particles, molecules and larger particles from solvents. The method is especially popular in water treatment and purification.

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kvasek [131]

Explanation:

A.

Yes

B.

2KHP + Mg(OH)2 = 2KOH + Mg(HP)2

KHP is an acidic salt which reacts with Mg(OH)2 which is a base via double displacement/decomposition reaction.

C.

• One approach is to prepare the solution volumetrically using KHP crystals.

• Preparing 1 liter of 0.1 M KHP you would add 0.1 moles of KHP

Molar mass of KHP(C8H5KO4)

= (12*8) + (5*1) + 39 + (16*4)

= 204 g/mol

Number of moles = mass/molar mass

= 20.4/204

= 0.1 mol.

• This is added to a 1 liter volumetric flask, add deionized water until near the fill line, stopper and mix

D.

Number of moles = molar concentration * volume

= 0.025 * 0.100

= 0.0025 mol

Equation for the reaction:

Ba(OH)2 + 2KHP --> Ba(KP)2 + 2H2O

1 mole of Ba(OH)2 reacted with 2 moles of KHP. By stoichiometry,

Number of moles of Ba(OH)2 = 0.0025/2

= 0.00125 mol.

Molarity = number of moles/volume

= 0.00125/0.01

= 0.125 M of Ba(OH)2.

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