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PSYCHO15rus [73]
3 years ago
5

The bill for lunch was 24.50 mr smith add a 20% tip how much did mr smith pay

Mathematics
1 answer:
miss Akunina [59]3 years ago
4 0

Answer:

Mr.Smith paid $29.4.

Step-by-step explanation:

Mr.Smith paid $24.5 plus additional 20% of $24.5, and to figure out the total amount that he paid, we need to know what is 20% of $24.50.

20% of $24.50 is:

\frac{20}{100}*24.5=0.2*24.6=4.9.

Mr.Smith paid additional $4.9; therefore, the total amount he paid was

$24.5 + $4.9 = $29.4.

Mr. smith paid $29.4.

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X+5.5+8=5x-13.5-4x what does x equal
wariber [46]

Answer:

There are no values of x that makes the equation true. or in other words ( no solution)

8 0
3 years ago
There are eight different jobs in a printer queue. Each job has a distinct tag which is a string of three upper case letters. Th
N76 [4]

Answer:

a. 40320 ways

b. 10080 ways

c. 25200 ways

d. 10080 ways

e. 10080 ways

Step-by-step explanation:

There are 8 different jobs in a printer queue.

a. They can be arranged in the queue in 8! ways.

No. of ways to arrange the 8 jobs = 8!

                                                        = 8*7*6*5*4*3*2*1

No. of ways to arrange the 8 jobs = 40320 ways

b. USU comes immediately before CDP. This means that these two jobs must be one after the other. They can be arranged in 2! ways. Consider both of them as one unit. The remaining 6 together with both these jobs can be arranged in 7! ways. So,

No. of ways to arrange the 8 jobs if USU comes immediately before CDP

= 2! * 7!

= 2*1 * 7*6*5*4*3*2*1

= 10080 ways

c. First consider a gap of 1 space between the two jobs USU and CDP. One case can be that USU comes at the first place and CDP at the third place. The remaining 6 jobs can be arranged in 6! ways. Another case can be when USU comes at the second place and CDP at the fourth. This will go on until CDP is at the last place. So, we will have 5 such cases.

The no. of ways USU and CDP can be arranged with a gap of one space is:

6! * 6 = 4320

Then, with a gap of two spaces, USU can come at the first place and CDP at the fourth.  This will go on until CDP is at the last place and USU at the sixth. So there will be 5 cases. No. of ways the rest of the jobs can be arranged is 6! and the total no. of ways in which USU and CDP can be arranged with a space of two is: 5 * 6! = 3600

Then, with a gap of three spaces, USU will come at the first place and CDP at the fifth. We will have four such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 4 * 6!

Then, with a gap of four spaces, USU will come at the first place and CDP at the sixth. We will have three such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 3 * 6!

Then, with a gap of five spaces, USU will come at the first place and CDP at the seventh. We will have two such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 2 * 6!

Finally, with a gap of 6 spaces, USU at first place and CDP at the last, we can arrange the rest of the jobs in 6! ways.

So, total no. of different ways to arrange the jobs such that USU comes before CDP = 10080 + 6*6! + 5*6! + 4*6! + 3*6! + 2*6! + 1*6!

                    = 10080 + 4320 + 3600 + 2880 + 2160 + 1440 + 720

                    = 25200 ways

d. If QKJ comes last then, the remaining 7 jobs can be arranged in 7! ways. Similarly, if LPW comes last, the remaining 7 jobs can be arranged in 7! ways. so, total no. of different ways in which the eight jobs can be arranged is 7! + 7! = 10080 ways

e. If QKJ comes last then, the remaining 7 jobs can be arranged in 7! ways in the queue. Similarly, if QKJ comes second-to-last then also the jobs can be arranged in the queue in 7! ways. So, total no. of ways to arrange the jobs in the queue is 7! + 7! = 10080 ways

3 0
3 years ago
Given that A = (4,3,-4), B = (2,8,-5) and C = (-5,5,-8), find the vector from A to the midpoint of BC.
viktelen [127]
Mid-point of BC, M=(2+(-5),8+5,-5+(-8))/2=(-1.5, 6.5, -6.5)
Vector from A to M = M-A=<(-1.5,6.5,-6.5)-(4,3,-4)>=<-11/2,7/2,-5/2>


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3 years ago
Please help me please :(
aleksklad [387]

Answer:

18

Step-by-step explanation:

There is a string that is 3 yards long that is divided into pieces that are 1/6 of yard long.  Divide the total length by the length it was divided into to find the number of pieces.

When dividing with fractions, the second number will be inverted and multiplied by the first number.

3 ÷ (1/6) = 3 × 6 = 18

You will have 18 pieces

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en un examen de la universidad ,el número de ingresantes es al número de postulantes como 2 es a 9.Si de los ingresantes la octa
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3 years ago
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