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NeX [460]
3 years ago
5

What is the surface area of the square pyramid? A net has a square base with side lengths of 2, and 4 triangles with heights of

3. square units
Mathematics
2 answers:
Gelneren [198K]3 years ago
7 0

Answer:

16 units²

Step-by-step explanation:

Surface area

= square + 4 triangles

= 2² + 4(½ × 2 × 3)

= 4 + 4(3)

= 4 + 12

= 16

Bess [88]3 years ago
5 0

Step-by-step explanation:

<u>Step 1:  Find the surface area of the square</u>

Area = s^2

Area = 2^2

Area = 4

<u>Step 2:  Find the surface area of the triangles</u>

Area = (b * h) / 2

Area = (2 * 3) / 2

Area = 3

Area of four triangles = 4 * 3 = 12

<u>Step 3:  Combine the Area's</u>

Square + Four Triangles

4 + 12

16

Answer: 16 units^2

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Mazyrski [523]

Answer:

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Step-by-step explanation:

If you draw out the triangles it is easier to see

8 0
3 years ago
Determine which situation could be represented by the system of linear equations given below.
Bezzdna [24]

Answer: Jane sells beaded bracelets for $2 each and beaded necklaces for $4 each. She sold 50 pieces of jewelry at the craft fair last weekend and made $160.

Step-by-step explanation: I just answer this and it's correct.

4 0
2 years ago
Directions: Using the digits 1 to 9, at most one time each, fill in the boxes to find the largest or smallest possible values fo
12345 [234]

9514 1404 393

Answer:

  smallest: 8x -3 = 4; 1y +9 = 2. total = -49/8

  largest: 1x -9 = 8; 2y +3 = 7. total = 19

Step-by-step explanation:

If we use variables to represent the box contents, we can write ...

  • ax -b = c
  • dy +e = f

Then the values of x and y are ...

  x = (c +b)/a

  y = (f -e)/d

For positive integer values of the variables, x will always be positive, and y may or may not be negative.

<h3>Smallest sum</h3>

For the sum to be the smallest, we must have x be as small as possible and the ratio (f-e)/d be as negative as possible.

x will be small for large 'a' and for (c+b) small. For y to be as negative as possible, we want 'd' and 'f' small and 'e' large. Best results are obtained for

  • 8x -3 = 4   ⇒   x = 7/8
  • 1y +9 = 2   ⇒   y = -7

For these coefficients, the sum is -6 1/8 = -49/8.

(note that the values of 'b' and 'c' can be swapped with no net effect)

<h3>Largest sum</h3>

For the sum to be the largest, we must have x as large as possible: (b+c) large and 'a' small. At the same time we must have y be positive and as large as possible: (f-e) positive and large, 'd' small. Best results are obtained for

  • 1x -9 = 8  ⇒   x = 17
  • 2y +3 = 7   ⇒   y = 2

For these coefficients, the sum is 19. Again, 'b' and 'c' can be swapped with no effect.

_____

<em>Additional comment</em>

These extreme values are verified by examination of the 60,480 possible permutations of the coefficients.

8 0
3 years ago
Read 2 more answers
Please anyone answer me
ollegr [7]

Let's divide the shaded region into two areas:

area 1: x = 0 ---> x = 2

ares 2: x = 2 ---> x = 4

In area 1, we need to find the area under g(x) = x and in area 2, we need to find the area between g(x) = x and f(x) = (x - 2)^2. Now let's set up the integrals needed to find the areas.

Area 1:

A\frac{}{1}  = ∫g(x)dx =  ∫xdx =  \frac{1}{2}  {x}^{2}  | \frac{2}{0}  = 2

Area 2:

A\frac{}{2}  = ∫(g(x) - f(x))dx

= ∫(x -  {(x - 2)}^{2} )dx

=  ∫( - {x}^{2}  + 5x - 4)dx

= ( - \frac{1}{3}{x}^{3} +   \frac{5}{2} {x}^{2}  - 4x)   | \frac{4}{2}

= 2.67 - ( - 0.67) = 3.34

Therefore, the area of the shaded portion of the graph is

A = A1 + A2 = 5.34

3 0
3 years ago
Please help. I will be constantly asking questions on the app to finish a class and i only have a day​
alekssr [168]

Answer: C 0\leq y\leq 5

Step-by-step explanation:

8 0
3 years ago
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