All categories

3 years ago

How can 7 1/5+(-8 3/5) be expressed as the sum of its integer and fractional parts

Mathematics

1 answer:

Nadya [2.5K]3 years ago

6 0

Answer:

see the explanation

Step-by-step explanation:

we know that

A mixed number is the sum of a integer and a fractional part

we have

$7\frac{1}{5}+(-8\frac{3}{5})$

$7\frac{1}{5}=7+\frac{1}{5}$

$-8\frac{3}{5}=-8-\frac{3}{5}$

substitute

$7+\frac{1}{5}+(-8-\frac{3}{5})$

Group terms

$(7-8)+(\frac{1}{5}-\frac{3}{5})$

$(-1)+(-\frac{2}{5})$

$-1\frac{2}{5}$

You might be interested in

Please help me.

user100 [1]

Average of 5 games is no more than 74
So total 5 games with average 74 is:

74 x 5 = 370

First 4 games:

77+ 71 + 77 + 67 = 292

Find highest score on the last game
370 - 292 = 78

So highest score on the game 5 you can shoot is 78

Answer is B. 78

8 0

3 years ago

Intersection point of Y=logx and y=1/2log(x+1)

GalinKa [24]

Answer:

The intersection is $(\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2})$ .

The Problem:

What is the intersection point of $y=\log(x)$ and $y=\frac{1}{2}\log(x+1)$ ?

Step-by-step explanation:

To find the intersection of $y=\log(x)$ and $y=\frac{1}{2}\log(x+1)$ , we will need to find when they have a common point; when their $x$ and $y$ are the same.

Let's start with setting the $y$ 's equal to find those $x$ 's for which the $y$ 's are the same.

$\log(x)=\frac{1}{2}\log(x+1)$

By power rule:

$\log(x)=\log((x+1)^\frac{1}{2})$

Since $\log(u)=\log(v)$ implies $u=v$ :

$x=(x+1)^\frac{1}{2}$

Squaring both sides to get rid of the fraction exponent:

$x^2=x+1$

This is a quadratic equation.

Subtract $(x+1)$ on both sides:

$x^2-(x+1)=0$

$x^2-x-1=0$

Comparing this to $ax^2+bx+c=0$ we see the following:

$a=1$

$b=-1$

$c=-1$

Let's plug them into the quadratic formula:

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{1 \pm \sqrt{(-1)^2-4(1)(-1)}}{2(1)}$

$x=\frac{1 \pm \sqrt{1+4}}{2}$

$x=\frac{1 \pm \sqrt{5}}{2}$

So we have the solutions to the quadratic equation are:

$x=\frac{1+\sqrt{5}}{2}$ or $x=\frac{1-\sqrt{5}}{2}$ .

The second solution definitely gives at least one of the logarithm equation problems.

Example: $\log(x)$ has problems when $x \le 0$ and so the second solution is a problem.

So the $x$ where the equations intersect is at $x=\frac{1+\sqrt{5}}{2}$ .

Let's find the $y$ -coordinate.

You may use either equation.

I choose $y=\log(x)$ .

$y=\log(\frac{1+\sqrt{5}}{2})$

The intersection is $(\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2})$ .

6 0

3 years ago

Pls help ill give brainliest

Maurinko [17]

Answer:

Step-by-step explanation:

-5g -6

Let g= -2

-5 (-2) -6

Multiply

10 -6

7 0

2 years ago

Read 2 more answers

Chris wants to paint the ceiling of his restaurant. The ceiling is in the shape of a square. Its side lengths are 55 feet. Suppo

d1i1m1o1n [39]

Answer:

11 cans

Step-by-step explanation:

Since you know that the ceiling is in the shape of a square and each side is 55ft, you can multiply 55x55 to get 3075, which is divided by 275 due to the amount of paint in a can. It would result in 11 cans, but if it were a decimal like 11.3, then you would need 12 cans since you can't split a can.

6 0

3 years ago

Read 2 more answers

Which statement best compares the volumes of the two rectangular prisms?

Dmitry [639]

Answer:

There is not enough information to compare the volume of the prisms.

Step-by-step explanation:

To find the volume of rectangular prisms, the length , width and height must be given. The volume of rectangular prisms is gotten by multiplying the three dimension: length, width and height which is expressed in cubic units. To compare the two volumes, the three dimensions must be given.

Hence, there is not enough information to compare.

3 0

3 years ago