Question

How can 7 1/5+(-8 3/5) be expressed as the sum of its integer and fractional parts

Answer 1

Answer:

see the explanation

Step-by-step explanation:

we know that

A mixed number is the sum of a integer and a fractional part

we have

$7\frac{1}{5}+(-8\frac{3}{5})$

so

$7\frac{1}{5}=7+\frac{1}{5}$

$-8\frac{3}{5}=-8-\frac{3}{5}$

substitute

$7+\frac{1}{5}+(-8-\frac{3}{5})$

Group terms

$(7-8)+(\frac{1}{5}-\frac{3}{5})$

$(-1)+(-\frac{2}{5})$

$-1\frac{2}{5}$