All categories

3 years ago

How can 7 1/5+(-8 3/5) be expressed as the sum of its integer and fractional parts

Mathematics

1 answer:

Nadya [2.5K]3 years ago

6 0

Answer:

see the explanation

Step-by-step explanation:

we know that

A mixed number is the sum of a integer and a fractional part

we have

$7\frac{1}{5}+(-8\frac{3}{5})$

$7\frac{1}{5}=7+\frac{1}{5}$

$-8\frac{3}{5}=-8-\frac{3}{5}$

substitute

$7+\frac{1}{5}+(-8-\frac{3}{5})$

Group terms

$(7-8)+(\frac{1}{5}-\frac{3}{5})$

$(-1)+(-\frac{2}{5})$

$-1\frac{2}{5}$

You might be interested in

Larry wants to buy some carpeting for his living room. The length of the room is 2 times the width and the total area of the roo

Phantasy [73]

The width is 2 and the length is 4 hope this helps!

7 0

3 years ago

Solve log (x + 1) = –x2 + 10 by graphing. Which equations should be graphed?

GarryVolchara [31]

Y2 = log (x+1) is the answer

4 0

3 years ago

Read 2 more answers

HELP YALL HELP PLEASE

kumpel [21]

Answer:

66 ur welcome

7 0

2 years ago

Triangle RST is shown. What is the y-coordinate of the final image of vertex T after the triangle is reflected over the x-axis f

gavmur [86]

Answer:

R¹(-7, -3) , S¹(-2, -1), T¹(-5, 4)

Step-by-step explanation:

Step(i):-

From the graph, the points are R(-4,5), S(1,3),T(-2,-2)

First, the points are reflected over the x-axis then transform in to

(x,y)→(x,-y)

R(-4,5)→R¹(-4,-5)

S(1,3)→S¹(1,-3)

T(-2,-2)→T¹(-2,2)

Step(ii):-

Next, The points are shifted to 3 units left then the transform

(x,y)→ (x -3 ,y)

R¹(-4,-5)→ R¹(-4-3, -5) → R¹(-7, -5)

S¹(1,-3) → S¹(1-3, -3) → S¹(-2, -3)

T¹(-2,2) → T¹(-2-3, 2)→ T¹(-5, 2)

Step(iii):-

Now again the points are shifted to '2' units up then transform to

(x,y) )→ (x ,y+2)

R¹(-7, -5+2) → R¹(-7, -3)

S¹(-2, -3+2) → S¹(-2, -1)

T¹(-5, 2+2) → T¹(-5, 4)

4 0

3 years ago

Homogenized milk has a density of 1.032 kg/L and heavy cream has a density of 1.005 kg/L at 10°C. At 10°C, a container holding 8

Bumek [7]

Answer:

It's heavy cream

Step-by-step explanation:

Homogenized milk has a density of 1.032 kg/L and

heavy cream has a density of 1.005 kg/L at 10°C.

At 10°C, a container holding 8 liters of liquid weighs 8.04 kilograms

To determine which container hold homogenized milk or heavy cream and How I know?

We findo the density of the measurements given and whatever it correspond to is what it is

First mass is 8.04kg

Liquid contained is 8 litres

SInce the density is kg/L

No need for conversion

Density = mass/volume = 8.04/8= 1.005kg/L

Heavy cream has a density of 1.005 kg/L at 10°C.

Therefore it correspond

5 0

3 years ago