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In proving  that C is the midpoint of AB, we see truly that C has Symmetric  property.
<h3>What is the proof about?</h3>
Note that:
 AB = 12
AC = 6.
BC = AB - AC
= 12 - 6 
=6
So, AC, BC= 6
Since C is in the middle, one can say that C is the midpoint of AB.
Note that the use of segment addition property shows: AC + CB = AB = 12
Since it has Symmetric property, AC = 6 and Subtraction property shows that CB = 6
Therefore,  AC = CB and thus In proving  that C is the midpoint of AB, we see truly that C has Symmetric  property.
See full question below
Given: AB = 12 AC = 6 Prove: C is the midpoint of AB. A line has points A, C, B. Proof: We are given that AB = 12 and AC = 6. Applying the segment addition property, we get AC + CB = AB. Applying the substitution property, we get 6 + CB = 12. The subtraction property can be used to find CB = 6. The symmetric property shows that 6 = AC. Since CB = 6 and 6 = AC, AC = CB by the property. So, AC ≅ CB by the definition of congruent segments. Finally, C is the midpoint of AB because it divides AB into two congruent segments. Answer choices: Congruence Symmetric Reflexive Transitive
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The Square Root Of 8100 Is 90. That Will Be The Only Square Root Because The Square Root Of 90 Is A Decimal So You Would Stop There.
        
                    
             
        
        
        
Answer:
Step-by-step explanation:
f(x)=(x²+20x+100) -3  because : 97 = 100 -  3
f(x) = (x+10)² -3 ....vertex form