Sam can solve 30 multiplication problems in 2 minutes how many can he solve in 20 Minutes
2 answers:
Hi there!
The question here gives us that Sam can solve 30 multiplication problems in 2 minutes, and we are asked to solve it in 20 minutes. There are many ways to get the answer, but I'll be showing you the easiest method.
<em>Let the number of problems Sam solves in 20 minutes be represented by x
</em><em /><em />First, write the given information.
30 problems = 2 minutes
x problems = 20 minutes
We can rewrite the given information like this -
Use cross multiplication to simplify further -
Divide both sides by 2 -
Therefore, Sam can do 300 problems in 20 minutes. Hope this helped!
The question here gives us that Sam can solve 30 multiplication problems in 2 minutes, and we are asked to solve it in 20 minutes. There are many ways to get the answer, but I'll be showing you the easiest method.
<em>Let the number of problems Sam solves in 20 minutes be represented by x
</em><em /><em />First, write the given information.
30 problems = 2 minutes
x problems = 20 minutes
We can rewrite the given information like this -
Use cross multiplication to simplify further -
Divide both sides by 2 -
Therefore, Sam can do 300 problems in 20 minutes. Hope this helped!
You might be interested in
Recall your d = rt, distance = rate * time
let's say the boat's rate is "b" in still water, and the current's rate is "c"
as the boat goes upstream, is not really going "b" fast, the water is not still anyway, is going much slower, is going " b - c ", because the current's rate is eroding speed because is going against the current.
as the boat goes downstream, is not going "b" fast either, is going faster, is going " b + c " fast, because is going downstream and thus with the current and the current is adding speed to it. notice, it takes longer going up, 5hrs, then coming down, 3hrs, same 150 on each way.
solve for "r"
what's the boat's rate? well, 30+r = b
let's say the boat's rate is "b" in still water, and the current's rate is "c"
as the boat goes upstream, is not really going "b" fast, the water is not still anyway, is going much slower, is going " b - c ", because the current's rate is eroding speed because is going against the current.
as the boat goes downstream, is not going "b" fast either, is going faster, is going " b + c " fast, because is going downstream and thus with the current and the current is adding speed to it. notice, it takes longer going up, 5hrs, then coming down, 3hrs, same 150 on each way.
solve for "r"
what's the boat's rate? well, 30+r = b