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Katarina [22]
4 years ago
9

The time required for a radioactive mass to reduce by a factor of 2 is called:

Chemistry
2 answers:
umka2103 [35]4 years ago
7 0

Answer:

half life would be the correct choice

Explanation:

Degger [83]4 years ago
4 0

The time required for a radioactive mass to reduce by a factor of 2 is called half-life.

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Which statement about scientific consensus is true?
Blababa [14]

what are the options?

reply in comments so i can help:)

3 0
3 years ago
why does diving 30m below sea level affect our bodies more than being in a building 30m above sea level?
yaroslaw [1]
Imagine you are in a swimming pool 30m deep. Assuming you know that water is denser than air, you would know that the 30m of water above you will carry more weight, and press down on your body. Say you were in a swimming pool 60m deep, you would be sandwiched between 30m of water pressing down on you, and the upthrust created by the 30m of water below you.

In a building 30m up, the pressure will be regulated, as you are in a building. The floor will be strong enough to support the weight of the body, and the body will not recoil into itself.
4 0
4 years ago
Read 2 more answers
What is the mole ratio of  to Fe?<br><br>1:3<br><br>1:4<br><br>3:1<br><br>4:3
kobusy [5.1K]

What is the mole ratio of  to Fe? if oxygen it is 4:3  Fe3O4

8 0
3 years ago
0.102 g of an unknown(non electrolyte) compound is dissolved in enough water to make 100. mL of a solution and has an osmotic pr
Leni [432]

Answer:

680 g/m is the molar mass for the unknown, non electrolyte, compound.

Explanation:

Let's apply the formula for osmotic pressure

π = Molarity . R . T

T = T° absolute (in K)

R = Universal constant gases

π = Pressure

Molarity = mol/L

As units of R are  L.atm/mol.K, we have to convert the mmHg to atm

760 mmHg  is 1 atm

28.1 mmHg is (28.1  .1)/760 = 0.0369 atm

0.0369 atm = M . 0.082 L.atm/mol.K . 293K

(0.0369 atm / 0.082 mol.K/L.atm . 293K) = M

0.0015 mol/L = Molarity

This data means the mol of solute in 1L, but we have 100mL so

Molarity . volume = mol

0.0015 mol/L . 0.1L = 1.5x10⁻⁴ mole

The molar mass will be: 0.102g / 1.5x10⁻⁴ m = 680 g/m

4 0
4 years ago
A sample of a compound contains 3.21 g of sulfur and 11.4 g of fluorine. Which of the following represents the empirical formula
Murrr4er [49]

Answer: The empirical formula will be SF_6

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of S= 3.21 g

Mass of F = 11.4 g

Step 1 : convert given masses into moles.

Moles of S =\frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{3.21g}{32g/mole}=0.1moles

Moles of F =\frac{\text{ given mass of F}{\text{ molar mass of F}}= \frac{11.04g}{19g/mole}=0.6moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For S= \frac{0.1}{0.1}=1

For F = \frac{0.6}{0.1}=6

The ratio of S: F= 1: 6

Hence the empirical formula is SF_6

7 0
3 years ago
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