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3 years ago

How many molecules of carbon dioxide, CO2, are present in 388.1 grams?

Chemistry

1 answer:

swat323 years ago

6 0

Answer:

53.11× 10²³ molecules

Explanation:

Given data:

Number of molecules of CO₂ = ?

Mass of CO₂ = 388.1 g

Solution:

Formula:

Number of moles = mass/ molar mass

Molar mass of CO₂ = 12× 1 + 16×2

Molar mass of CO₂ = 44 g/mol

Now we will put the values in formula.

Number of moles = 388.1 g/ 44 g/mol

Number of moles = 8.82 moles

Now we will calculate the number of molecules by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ molecules

8.82 mol × 6.022 × 10²³ molecules / 1 mol

53.11× 10²³ molecules

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If you have a volume of 55 L and a density of 2 kg/L, what is the mass?

ASHA 777 [7]

Answer:

110kg

Explanation:

Density = mass / volume

Mass = density x volume

Given

Density = 2kg/l

Volume = 55l

Mass = 2kg/l x 55l

Mass = 110 kg

I hope this was helpful, Please mark as brainliest

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4 years ago

0.20 g of sodium hydroxide (NaOH) pellets are dissolved in water to make 4.5 L of solution. What is the pH of this solution?

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3 years ago

A central atom that is sp3 hybridized could bind up to how many other atoms?

inna [77]

Answer: up to 4 other atoms.

Explanation:

<em>Hybridization sp</em>³ means that the atom has 4 equal orbitals formed by the combination of 1 s and 3 p orbitals.

Each of these sp³ orbitals is a place for a chemical bonding.

Hence, since each orbital is able to bind a different atom, you conclude that <em>a central atom that is sp³ hydridized could bind up to 4 other atoms.</em>

This is precisely the case for carbon (C) atoms.

Carbon has atomic number 6. So its electron configuration is 1s² 2s²p².

The four electrons in the level 2, those shown in 2s² 2p², are in two different orbitals: two are in the orbital 2s and two are in the orbitals 2p.

This diagram shows how those 4 electrons fill the orbitals

2s⇅ 2px↑ 2py↑

The two 2s electrons have lower energy level than the 2px and 2 py electrons, but the difference is not too big.That is why one of the electrons in the 2s ortital can be promoted to the empty 2pz orbital, and you get 4 equal hydridized ortibals, so called sp³.

And that is why, carbon (C) ends up with 4 equal (hydridized) orbitals which can bind up to 4 different atoms, including other carbon atoms, and so, form long chains and, virtually, infinite compounds.

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4 years ago

Butane (C4H10) has a heat of vaporization of 22.44 kJ/mol and a normal boiling point of -0.4 ∘C. A 250 mL sealed flask contains

erastova [34]

Given that:

The heat of vaporization = 22.44 kJ/mol = 22440 J/mol
normal boiling point which is the initial temperature = 0.4° C = (273 + (-0.4))K = 272.6 K
volume = 250 mL = 0.250 L
Mass of butane = 0.8 g
the final temperature = -22° C = (273 + (-22)) K = 251 K

The first step is to determine the vapor pressure at the final temperature of 251K by using the Clausius-Clapeyron equation. This is following by using the ideal gas equation to determine the numbers of moles of butane gas. After that, the mass of butane present in the liquid is determined by using the relation for the number of moles.

Using Clausius-Clapeyron Equation:

$\mathbf{In (\dfrac{P_2}{P_1} )= -\dfrac{\Delta H_{vap}}{R}(\dfrac{1}{T_2} - \dfrac{1}{T_1})}$